3 years ago

Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: f (h(x)) and. g (f (x))

1 answer:

7 0

F((h(x)) = 2(x^2 + 1) - 1 = 2x^2 + 1 (replace the x in f(x) by h(x))

g ( f(x)) = 3(2x - 1) = 6x - 3 (replace the x in g(x) by f(x))

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<h2>Answer:</h2>

$b. \ \boxed{32 \sq. \ units}$

<h2>Step-by-step explanation:</h2>

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, $b_{1}\,and\,b_{2}$ . Also, the height $H$ of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of $b_{1},b_{2}\:and\:H$ is: