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3 years ago

Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: f (h(x)) and. g (f (x))

1 answer:

7 0

F((h(x)) = 2(x^2 + 1) - 1 = 2x^2 + 1 (replace the x in f(x) by h(x))

g ( f(x)) = 3(2x - 1) = 6x - 3 (replace the x in g(x) by f(x))

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find the equation of a line that passes through (-3,1) and (-1,-2) and write it in standard form. please help me !

Savatey [412]

Find the slope first
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now use the slope and either point to write in point slope form
y-1=.25(x-2)
y-1=¼x-½

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then put in the correct order

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3 years ago

Find the volume of the cone shown below.

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

The formula for volume of cone is $V=\frac{1}{3}\pi r^2 h$

Where

V is the volume

r is the radius of the circular base

h is the height of the cone

In the diagram shown, we can clearly see that height is 12, radius is 9. We can simply plug them into the formula and get our exact answer (leaving pi as pi):

$V=\frac{1}{3}\pi (9)^2(12)\\=324 \pi$

correct answer is D

6 0

2 years ago

Read 2 more answers

11z > -33 help please

stich3 [128]

11z > -33

11z / 11 > 33 / 11

z > 3

Hope it helps!

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2 years ago

Please show your work.

Inessa [10]

The answer would be a reflection over the x-axis and then a reflection over the y-axis

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3 years ago

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Find an equation of the parabola with focus (2, −3) and directrix y = 1.

Likurg_2 [28]

Answer:

Step-by-step explanation:

The correct option is option (C).

The required equation of the parabola is

Step-by-step explanation:

Formula:

The distance of a point (x₁,y₁) from a line ax+by+c=0 is

The distance between two points (x₁,y₁) and (x₂,y₂) is

Given that, the focus of the parabola is (2,3) and directrix y= - 1.

We know that, a parabola is the locus of points that equidistant from the directrix and the focus.

Let any point on the parabola be P(x,y) .

The distance of P from the directrix is

=y+1

The distance of the point P from the focus (2,3) is

According to the problem,

The required equation of the parabola is

5 0

3 years ago