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3 years ago

Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: f (h(x)) and. g (f (x))

1 answer:

7 0

F((h(x)) = 2(x^2 + 1) - 1 = 2x^2 + 1 (replace the x in f(x) by h(x))

g ( f(x)) = 3(2x - 1) = 6x - 3 (replace the x in g(x) by f(x))

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How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

elena-s [515]

Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have

$\dfrac{2.5}{x+10}=0.1\implies25=x+10\implies x=15$

and so you would need to add 15 L of pure water to get the desired concentration of acid.

8 0

3 years ago

Which is the equation of the line that passes through the point (-5, -2)

Lilit [14]

Answer:

F) y=3x+13

Step-by-step explanation:

y-y1=m(x-x1)

y-(-2)=3(x-(-5))

y+2=3(x+5)

y=3x+15-2

y=3x+13

5 0

2 years ago

Type the correct answer in each box. Use numerals instead of words.

stira [4]

The system of equations when been placed in a matrix yields

$\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the equation:

y = 650x + 175 and;

y = 25080 - 120x

Rearranging the equations gives:

650x - y = -175 and;

120x + y = 25080

Placing the equations in a matrix gives:

$\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]$

The system of equations when been placed in a matrix yields

$\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]$

Find out more on equation at: brainly.com/question/2972832

#SPJ1

6 0

2 years ago

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.