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Vedmedyk [2.9K]
3 years ago
11

How do you differentiate y = 3x3 - 2x-4

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0

Answer:

y' = 9x^2 + 8x^-5

Step-by-step explanation:

General Principle

y' = ax^b

y' = a*b * x^(b-1)

Solution

3x^3 = 3*3x^(3-1)

3x^3 = 9x^2

-2x^-4  = -2*-4 x ^(-4 - 1)

-2x^-4 = 8 x ^-5

Answer

y' = 9x^2 + 8x^-5

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Answer:

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Step-by-step explanation:

Equation

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3 years ago
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Prove that for any natural n the number 3^(n+4)−3^n is divisible by 16.
gtnhenbr [62]

Answer:

Proved (See Explanation)

Step-by-step explanation:

Show that 3ⁿ⁺⁴ - 3ⁿ is divisible by 16.

This is done as follows

\frac{3^{n+4} - 3^n}{16}

From laws of indices;

aᵐ⁺ⁿ = aᵐ * aⁿ.

So, 3ⁿ⁺⁴ can be written as 3ⁿ * 3⁴.

\frac{3^{n+4} - 3^n}{16} becomes

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Factorize

\frac{3^n(3^4 - 1)}{16}

\frac{3^n(81 - 1)}{16}

\frac{3^n(80)}{16}

3ⁿ * 5

5(3ⁿ)

<em>The expression can not be further simplified.</em>

<em>However, we can conclude that when 3ⁿ⁺⁴ - 3ⁿ is divisible by 16, because 5(3ⁿ) is a natural whole number as long as n is a natural whole number.</em>

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3 years ago
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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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