Ms. hernandez has 100 to spend on parking and admission to the zoo. The park will cost $7 and admission tickets will cost $15.50
1 answer:
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Distribute
-pd-pz=-2z+59
add 2z both sides
-pd-pz+2z=59
add pd to both sides
-pz+2z=59+pd
2z-pz=59+pd
undistribute z
z(2-p)=59-pd
divide bot sides by 2-p
-pd-pz=-2z+59
add 2z both sides
-pd-pz+2z=59
add pd to both sides
-pz+2z=59+pd
2z-pz=59+pd
undistribute z
z(2-p)=59-pd
divide bot sides by 2-p
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.