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tatuchka [14]
2 years ago
14

Can you please help me l don’t understand

Mathematics
1 answer:
Keith_Richards [23]2 years ago
5 0
It is rounded to nearest 10 so
If I have 15
It is rounded to 20
But if I have 14
It is rounded to 10

Dose this help
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In ​ kite PQRS ​, TS=6 cm and TP=8 cm
asambeis [7]
PQ=17
RS=14


hope it help
6 0
3 years ago
Read 2 more answers
Can someone please help me with this!!!!!<br><br> 2/5 ÷ 8 1/2 = ?
pav-90 [236]
The answer would be 4/85


1. 2/5 ÷ 8 * 2 + 1  over 2

2. 2/5 ÷ 16 + 1 over 2

3. 2/5 ÷ 17/2

4. 2/5 * 2/17

5. 2 * 2 over 5 * 17

6. 4 over 5 * 17

7. finally 4/85
7 0
3 years ago
Read 2 more answers
Factor of x^3-x^2-24x-36
Basile [38]
The trial and error method is used to find an initial factor:
If we let f(x) = x³ - x² - 24x - 36 and all we have to do is sub' in values of x until
f(x) = 0, we can use this to find an initial factor by the factor theorem:
f(1) = (1)³ - (1)² - 24(1) - 36 = -60
f(2) = (2)³ - (2)² - 24(2) - 36 = -80
f(5) = (5)³ - (5)² - 24(5) - 36 = -56
*** f(6) = (6)³ - (6)² - 24(6) - 36 = 0 ***

f(6) = 0 so (x - 6) is a factor of f(x).
This means that: f(x) = x³ - x² - 24x - 36 = (x - 6)(ax² + bx + c).
To find a,b and c, use long division (or inspection) to divide x³ - x² - 24x - 36 by x - 6.
The other 2 factors of f(x) can then be found by factorizing the
ax² + bx + c quadratic the way you would with any other quadratic (i.e. by quadratic formula, CTS or inspection).
5 0
3 years ago
Find the coordinates of the missing endpoint if P is the midpoint of Line Segment NQ.
dimaraw [331]
  • Midpoint formula is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) .
<h3>19.</h3>

So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such: \frac{x+2}{2}=5 From here we can solve for the x-coordinate of Q.

Firstly, multiply both sides by 2: x+2=10

Next, subtract both sides by 2 and your x-coordinate is x=8

With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

\frac{y+0}{2}=2\\ y=4

<u>Putting it together, the missing endpoint is (8,4).</u>

<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>

<h3>20.</h3>

\frac{x+5}{2}=6\\ x+5=12\\ x=7

\frac{y+4}{2}=3\\ y+4=6\\ y=2

<u>The missing endpoint is (7,2).</u>

<h3>21.</h3>

\frac{x+3}{2}=-1\\ x+3=-2\\ x=-5

\frac{y+9}{2}=5\\ y+9=10\\y=1

<u>The missing endpoint is (-5,1).</u>

8 0
3 years ago
Evaluate 15r -1 when r=5
alukav5142 [94]

Answer:

74

Step-by-step explanation:

You just have to substitute r with 5.

Now, the equation looks like this:

15(5)-1

Next, solve 15*5 first according to PEMDAS

And 15*5 equals 75

\frac{\left[\begin{array}{ccc}1&5\\5\\\end{array}\right] }{75}

Lastly, do 75-1 which equals 74

\frac{\left[\begin{array}{ccc}7&5\\-1\\\end{array}\right] }{74}

Therefore, 74 is your answer.

3 0
2 years ago
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