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Illusion [34]
3 years ago
9

In triangle pqr, rs=4 and qs=6. find ps

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
6 0

Answer:

PS=2\sqrt{6}

Step-by-step explanation:

we are given triangle as

we know that

triangle PRS and triangle PQS are similar

so, the ratios of their sides must be equal

we get

\frac{RS}{PS}=\frac{PS}{QS}

now, we are given

RS=4

QS=6

we can plug it

\frac{4}{PS}=\frac{PS}{6}

PS^2=6\times 4

PS^2=24

now, we can solve for PS

PS=2\sqrt{6}

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</span></span></span></span> <span><span> 5x2-23x=-26</span> </span>Two solutions were found :<span><span>  x = 2 </span><span>  x = 13/5 = 2.600
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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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Step by step solution :Skip Ad
<span> Step  1  :</span><span>Equation at the end of step  1  :</span><span> (5x2 - 23x) - -26 = 0 </span><span> Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> 5x2-23x+26</span> 

The first term is, <span> <span>5x2</span> </span> its coefficient is <span> 5 </span>.
The middle term is, <span> -23x </span> its coefficient is <span> -23 </span>.
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Step-1 : Multiply the coefficient of the first term by the constant <span>  5 • 26 = 130</span> 

Step-2 : Find two factors of  130  whose sum equals the coefficient of the middle term, which is  <span> -23 </span>.

<span><span>       -130    +    -1    =    -131 <span>
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</span> </span> <span>       -26    +    -5    =    -31 <span>
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