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Vitek1552 [10]
3 years ago
6

Này

Mathematics
1 answer:
Lunna [17]3 years ago
8 0

Answer:

what did he sayyyyyyy

Step-by-step explanation:

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An object moves from the position +16 m to the position +47 m in 12 s. What is its total displacement? What is its average veloc
Brrunno [24]

Given that an object moves from the position +16 m to the position +47 m in 12 s. Now we need to find about what is its total displacement and what is its average velocity.

We know that displacement is the object's overall change in position.

So total displacement is given by:

Displacement = (+47) - (+16) = +31


Now velocity is given by ratio of displacement and time so final answer for velocity will be :

Velocity=\frac{displacement}{time}=\frac{+31}{12}=2.583333

Which is approx 2.6 m/s.

5 0
3 years ago
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A ramp that is used to load a truck makes supplementary angles with the ground. The ramp has an incline (<1) of 28. What is t
jeka94

Answer:

Step-by-step explanation:

two angles are said to be supplementary if their sum is 180 degrees

Hence <1 + <2 = 180

Given

<1 = 28

Required

<2

Substitute into the formula

28+<2 =180

<2 = 180-28

<2= 152

Hence the measure of <2 is 152 degrees

7 0
4 years ago
Can somebody plz help answer these questions correctly (only if u know how to do this) thanks :D!
nignag [31]
14. Range=22 Mean= 31.2
15. Range=33 Mean= 88.2
16. Range= 81 Mean= 161.3
To find range you take the smallest number and the largest number and subtract them. To find mean you add all of the totals together and then divide by how many numbers are given.
4 0
3 years ago
Please help is for noww
Artemon [7]

Answer:

25¢

Step-by-step explanation:

3 0
3 years ago
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Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa
xxMikexx [17]

Answer:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      32   18    50

Medium                                 68     7    75

Large                                     89    11    100

_____________________________________

Total                                     189    36   225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1:  NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*189}{225}=42

E_{2} =\frac{50*36}{225}=8

E_{3} =\frac{75*189}{225}=63

E_{4} =\frac{75*36}{225}=12

E_{5} =\frac{100*189}{225}=84

E_{6} =\frac{100*36}{225}=16

And the expected values are given by:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      42    8    50

Medium                                 63     12    75

Large                                     84    16    100

_____________________________________

Total                                     189    36   225

And now we can calculate the statistic:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0
3 years ago
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