Answer:
i) Probability that both candidates employed are women = 5/14
ii) Probability that the second candidate is a woman = 5/8
iii) Probability that the first candidate is a woman given that second one is a woman = 4/5
Step-by-step explanation:
Let the probability that a man is employed be P(M) = 3/8
Probability that a woman is employed P(W) = 5/8
a) Probability that both candidates employed are women = (5/8) × (4/7) = 5/14
b) Probability that the second candidate is a woman = (probability that first candidate is a man and second candidate is a woman) + (probability that first candidate is a woman & second candidate is a woman)
= (3/8)(5/7) + (5/8)(4/7) = (15/56) + (20/56) = 35/56 = 5/8
c) Probability that the first candidate is a woman given that second one is a woman
Given that the second candidate was a women, means that the first candidate-women was selected among other four women.
Probability = (4/8)/(5/8) = 4/5
1.7-3-2.4y= 12y-11.64
-1.3-2.4y = 12y - 11.64
-2.4y = 12y - 11.64
-14.4y = -10.34
y= 10.34/14.4= 5.17/7.20 or 517/720
Answer:
cool
Step-by-step explanation:
whats ur question about it?
Answer:
9
Step-by-step explanation:
you can always use guess-and-check:
124 seems rather high
(6)P(2) = 6!/4! = 6x5 ≠ 72
(9)P(2) = 9!/7! = 9x8 = 72
Are you asking for a name?
M is a subset of u.
Is there something further?
