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3 years ago

the area of a triangular sign is 96 ft^2 (96 ft squared). if the base of the sign is 16 feet, what is the height of the sign?

Mathematics

1 answer:

lana66690 [7]3 years ago

7 0

Answer:

The height of the triangle is 12 feet.

Step-by-step explanation:

The area of a triangle is A = 1/2(b * h).

1/2(b * h) = A

b * h = 2A

h = 2A/b

Now substitute in the variables.

h = 2(96)/(16)

h = 192/16

h = 12

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4 years ago

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Orlov [11]

ANSWER
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EXPLANATION

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$\csc(x) = \frac{5}{3}$

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$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
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We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

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$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

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The correct answer is D

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