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Delvig [45]
4 years ago
5

Having trouble with this...

Mathematics
1 answer:
vladimir1956 [14]4 years ago
5 0

Step-by-step explanation:

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Three equivalent ratios for 6: 54
vodka [1.7K]
Treat it as a fraction where it must stay equal
6/54
with fractions, you can do anything as long as you do it so top and bottom
so 6/54=1/9=2/18=3/27=4/36=5/45 etc

but don't forget to convert back to ratios
so some examples are 1:9
2:18
3:27
4:35
5:45

4 0
3 years ago
Identify the circumference of ⊙S in which A=64π ft^2. HELP ASAP!!
Vika [28.1K]

Answer:

C = 16π ft

Step-by-step explanation:

If we know the area

A = pi r^2

64 pi = pi r^2

Divide each side by pi

64 = r^2

Take the square root of each side

8 = r

The radius is 8

Now we can find the circumference

C = 2 *pi*r

C = 2*pi*8

C = 16pi

5 0
3 years ago
Read 2 more answers
I donot understand at all
loris [4]

Answer:

sorry i dont understand either!!!

Step-by-step explanation:

8 0
3 years ago
What is a rounded number to 37.510
TiliK225 [7]
To round it to the nearest unit it would be 38. To round it to the nearest ten it would be 40.
3 0
3 years ago
Use spherical coordinates to find the limit. [Hint: Let x = rho sin(ϕ) cos(θ), y = rho sin(ϕ) sin(θ), and z = rho cos(ϕ), and no
shutvik [7]

Answer:

lim (x, y, z) → (0, 0, 0) [x*y*z]/(x^2+y^2+z^2)=0

Step-by-step explanation:

First, we need to put the spherical coordinates equations that we will use in our problem  

x = p*sin∅cos Ф

y = p*sin∅sinФ

z=p*cos∅

Then we will state the problem  

lim (x, y, z) → (0, 0, 0)  [x*y*z]/(x^2+y^2+z^2)

Using the spherical coordinates we get  

(x^2+y^2+z^2) = p^2  

Which will make our limit be  

lim p→0+ [p*sin∅cos Ф*p*sin∅sinФ *p*cos∅]/(x^2+y^2+z^2)

after solving limit:

lim (x, y, z) → (0, 0, 0) [x*y*z]/(x^2+y^2+z^2)=0

4 0
3 years ago
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