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3 years ago

What is the L.C.M of 45 80 and 135

Mathematics

2 answers:

Drupady [299]3 years ago

8 0

Answer:

the answer is (that I found) is 2160

Vinvika [58]3 years ago

6 0

Answer:

LCM = 2160

Step-by-step explanation:

lcm of 45 80 and 125 is 2160 because LCM = 2160

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I NEED HELP ASAP PLEASE

Ahat [919]

Answer: Domain: 0,1,2,3 and 4 and Range: 1,2,4,8 and 4

Step-by-step explanation:

The domain is the set of all inputs that makes the function definable. As we see the function looks like an exponential function which means the domain is all real numbers.

So the inputs are 0,1,2,3 and 4

the outputs are 1,2,4,8 and 4

3 0

3 years ago

Find integra of xlnxdx

Mademuasel [1]

Answer:

$\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Increase the power by 1, then divide by the new power.

Given indefinite integral:

$\displaystyle \int x \ln x \:\: \text{d}x$

To integrate the given integral, use Integration by Parts:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$

Learn more about integration here:

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5 0

2 years ago

Can anyone help me with this?

Maurinko [17]

Answer:

D. -6m²n² + 10m²n + 8mn² - 10mn

Step-by-step explanation:

(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)

Apply the distributive property to remove the parentheses

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

Combine like terms together and arrange in standard form

-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn

-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn

-6m²n² + 10m²n + 8mn² - 10mn

5 0

3 years ago

Let f(t) give the number of liters of fuel oil burned in t days, and w(r) the liters burned in r weeks. Find a formula for w by

viktelen [127]

Answer:

7 f(t)

Step-by-step explanation:

So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.

w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.

As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:

w(r) = w[7f(t)]

So, we represented the liters in one week by it measure of days.

So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:

w (r) = w[7 f(t)] = 7 f(t)

Here we hace the w function represented in terms of t instead of r.

3 0

3 years ago

5a + 18 < −27 pre algibra

Grace [21]

Answer:

X < -9

Step-by-step explanation:

5a +18 < -27

5a < -27 -18

5a < - 45

5a/5 < - 45/5

a < - 9

Answred by Gauthmath

5 0

3 years ago

Read 2 more answers