Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
Answer:
1. C. Yes, because a sum of cubes can be factored
2a. false
2b. false
2c. true
2d. false (based on what is written in the equation; refer to step-by-step)
Step-by-step explanation:
1. Both 3 and 8 can be cubed, which is why x^3+8 can be factored (x+2)(x^2-2x+4)
2a. a^2-b^2 can be factored by the perfect square rule, so it should be (a-b)^2
2b. both terms are perfect squares, so you can factor, making it (a+b)(a-b)
2c. You can factor using the perfect square rule, making it (a+b)^2
2d. Most of what is in the equation is true, yet the correct solution would be (a-b)(a^2+ab+b^2)
Answer:
Step-by-step explanation:
is an arithmetic progression with ratio=4
a1=5
a2=a1+4=5+4=9
a3=a2+4=9+4=13
...............
a n+1 = a n+4
Prime factorizations - Wednesday work
1. 44 2^2 • 11
2. 125 5^3
3. 85 5 • 17
4. 39 3 • 13
5. 63 3^2 • 7
6. 240 2^4 • 3 • 5
7. 87 3 • 29
8. 45 3^2 • 5
