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2 years ago

Fred is landscaping his backyard. He needs to create concrete steps with two levels. He has about

Mathematics

1 answer:

GenaCL600 [577]2 years ago

4 0

Answer: 13 Since Handyman Negri's has performed substantially all of the terms of the contract

Step-by-step explanation: pls mark brainliest

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HERES THIS QUESTION PLEASE HELP

Oxana [17]

27 hours in the maximum hours

7 0

2 years ago

PLease help me solve this

Mnenie [13.5K]

Answer: 729

Step-by-step explanation:

$\frac{1}{3^{-2} * 3^{-4} * (-1)^{2} }$

3^-2 = 1/9

3^-4 = 1/81

(-1)^2 = 1

1/(1/9 * 1/81 * 1)

1/ 1/729 = 729

4 0

2 years ago

Sue and cows have $20 left for cab fare home because there is three dollars per mile plus $2 fix charge what is the maximum numb

-Dominant- [34]

Answer:

The maximum number of miles they can travel is 6 miles.

Step-by-step explanation:

Because of the fix charge of $2, the amount of money left for the rest of the trip is $18. In order to find how many miles $18 cover when the cab charges $3 per hour, 18 is divided by 3. 18/3=6.

4 0

3 years ago

What is 86.92 in pi terms

trasher [3.6K]

Assume that pi is approx. 3.14. Then 86.92 = approx. 27 2/3 times pi, or

86.92 is approx. equal to 83pi/3.

6 0

3 years ago

Use the following matrices, A, B, C and D to perform each operation.

Vinvika [58]

Step-by-step explanation:

$A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]$

$B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]$

$C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]$

$D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]$

$1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]$

$2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]$

$3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]$

$5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}$

6 0

3 years ago