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GrogVix [38]
3 years ago
13

Find the domain of the rational expression: x-3/2x-8

Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:

\huge\boxed{x\neq4\to x\in\mathbb{R}\backslash\{4\}}

Step-by-step explanation:

\dfrac{x-3}{2x-8}

We know: the denominator must be different than 0.

Therefore

2x-8\neq0        <em>add 8 to both sides</em>

2x-8+8\neq0+8

2x\neq8             <em>divide both sides by 2</em>

\dfrac{2x}{2}=\dfrac{8}{2}\\\\x\neq4

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Zolol [24]

Answer:

2) Yes

3) No

4) Yes

5) 2x + 8

6) 5(x - 8)

7) 3x + 21

Hope this helps :)

5 0
3 years ago
Anybody? need help asap
VladimirAG [237]

Answer:

<em>K</em>=<em>2h</em>

<em>k</em><em>=</em><em>0.5h</em>

<em>k</em><em>=</em><em>h</em><em> </em><em>+</em><em> </em><em>1</em>

<em>k</em><em>=</em><em> </em><em>0.5h</em><em> </em><em>+</em><em> </em><em>1</em><em>0</em>

7 0
3 years ago
Are the triangles congruent? Why or why not?
Mariulka [41]

Answer:

Yes, because they are identical to eachother

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can anyone help me with number 36? I’m trying to figure out how to do this am I’m having a lot of problems. The answer is in the
zubka84 [21]

You have 9i in the denominator. The goal is to have a real denominator. 9i is imaginary. i * i = -1 which is real. If you multiply the denominator by i, the denominator will be real. Since this is a fraction, we multiply the numerator and denominator by i.

\dfrac{-6 - 10i} {9i } \times \dfrac{i}{i} =

= \dfrac{(-6 - 10i)i}{(9i)i}

= \dfrac{-6i - 10i^2}{9i^2}

= \dfrac{-6i - 10(-1)}{9(-1)}

= \dfrac{-6i + 10}{-9}

= \dfrac{6i - 10}{9}

= \dfrac{-10 + 6i}{9}

= \dfrac{-10}{9} + \dfrac{6i}{9}

= \dfrac{-10}{9} + \dfrac{2i}{3}

8 0
3 years ago
25 - (10 = 5) =<br><br> 1. 3<br> 2. 5<br> 3.20<br> 4. 23<br><br> Please help me:)
Illusion [34]

Answer:

if the question is 25-{10-5}

then the answer is 25-5

20

4 0
3 years ago
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