Answer:
2.5 half-lives
Step-by-step explanation:
Find 
in 
given 
is the amount after the time 
, 
`is the initial amount, is the half-life
We know that after half-life there will be twice less the initial quantity:
.
Simplifying gives 
Plugging this into the initial equation, we obtain that 
or 
Finally, just plug in the given values and find the unknown one.
From 
, we have that 
= 
So you should get: 
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Answer:
yeah
Step-by-step explanation:
Answer
Median bisects the line.
D≡(
2
−3+5
,
2
−9−8
)≡(1,
2
−17
)
E≡(−
2
1+5
,
2
6−8
)≡(2,−1)
F≡(−
2
1−3
,
2
6−9
)≡(−2,
2
−3
)
∴ equation of AD:(y−y
1
)=(
x
2
−x
1
y
2
−y
1
)
AD
(x−x
1
)
⇒(y−6)=
⎝
⎜
⎜
⎛
1+1
2
−17
−6
⎠
⎟
⎟
⎞
(x+1)⇒(y−6)=−
4
29
(x+1)
⇒
4
29
x+y−6+
4
29
=0
AD⇒29x+4y+5=0
equation of BE:(y+9)=(−
2+3
1+9
)
BE
(x+3)
⇒(y+9)=
5
8
(x+3)⇒5y+45=8x+24
BE⇒8x−5y−21=0
Equation of CF:(y+8)=
⎝
⎜
⎜
⎛
−2−5
−
2
3
+8
⎠
⎟
⎟
⎞
CF
(x−5)
⇒(y+8)=−
14
13
(x−5)⇒14y+112=−13x+65
CF:13x+14y+47=0
Answer:
2/15
Step-by-step explanation:
Step one:
given data
sample space
1 elephant,
4 bears,
3 cats, and
2 dogs.
sample size= 1+4+3+2= 10
Required:
By selecting without replacement, the probability that she chooses a bear both times
Step two:
the first event= Pr(bear)= 4/10= 2/5
the second event, the sample size is now 9 and the number of bears is now 3
Pr(bear)= 3/9= 1/3
Hence, the probability that she chooses a bear both times
= 2/5*1/3
=2/15
3x3x3x3 = 81
x.x.x.x = x^4
2x2x2x2 = 16
B. 81x^4/16
Answer:
52.500 by 52.500 inches
Step-by-step explanation:
The rectangle with maximum area will be a square. Its side length will be 1/4 the perimeter, so is 210/4 = 52.5 inches.
The figure is a 52.500 inch square. The interval of optimization is <em>closed</em>.
_____
Side lengths are restricted to the interval 0 to 105 inches.
__
Any n-sided polygon with a given perimeter will have its maximum area when the polygon is regular. A regular 4-gon is a square.
