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Lina20 [59]
3 years ago
5

PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER!

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0
3x3x3x3 = 81
x.x.x.x = x^4
2x2x2x2 = 16

B. 81x^4/16
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Assume that​ women's heights are normally distributed with a mean given by mu equals 62.3 in​, and a standard deviation given by
Salsk061 [2.6K]

Answer: a)  0.6141

b) 0.9772

Step-by-step explanation:

Given : Mean : \mu= 62.3\text{ in}

Standard deviation : \sigma = \text{2.4 in}

The formula for z -score :

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

a) Sample size = 1

For x= 63 in. ,

z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{1}}}=0.29

The p-value = P(z

0.6140918\approx0.6141

Thus, the probability is approximately = 0.6141

b)  Sample size = 47

For x= 63 ,

z=\dfrac{63-62.3}{\dfrac{2.4}{\sqrt{47}}}\approx2.0

The p-value = P(z

=0.9772498\approx0.9772

Thus , the probability that they have a mean height less than 63 in =0.9772.

8 0
3 years ago
A dance studio offers ballet and hip-hop classes. The studio has 8 ballet classes for every 12 hip-hop classes. How many hip-hop
olga nikolaevna [1]
I think the answer is 1.5
5 0
3 years ago
Read 2 more answers
Please I need help step by step
zaharov [31]
To find the surface area, you need to do the following:
A side of the figure is a trapezoid, so you should do 13+5x7 (since there are 2 of the same sides there is no need to divide by two.) and it should equal 126. To find the area of the top of the figure, you need to do 5x2 which equals 10. The area of the bottom of the figure is 26 (13x2), then do 2x3x2 to get the sides on the left and right of the figure. After all of this, add them together. (126+10+26+12=174.)
The surface area should be 174mm.
6 0
3 years ago
5c+16.5=13.5+10c PLease answer quicly
frosja888 [35]
Remember you can do anything to an equation as long as you do it to both sides

5c+16.5=13.5+10c
minus 5c both sides
16.5=13.5+5c
minus 13.5 from both sides
3=5c
divide both sides by 5
3/5=c
4 0
3 years ago
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What is the solution to the equation 41/5 =15-(2x+3)
likoan [24]
\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}
4 0
3 years ago
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