The range of the function is y >= 2
<h3>How to determine the range of the function?</h3>
The equation of the function is given as:
f(x) = 5|x - 7| + 2
The above function is an absolute value function.
An absolute value function is represented as:
f(x) = a|x -h| + k
Where
Leading coefficient = a
Vertex = (h, k)
This means that
a = 5
(h, k) = (7, 2)
If a is positive, then the vertex is a minimum
This means that the vertex (7, 2) is a minimum
Remove the x value
y = 2
Express as a range
y >= 2
Hence, the range of the function is y >= 2
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Answer:
B
Step-by-step explanation:
Given
x² + 14x = 51
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(7)x + 49 = 51 + 49 , that is
(x + 7)² = 100 ( take the square root of both sides )
x + 7 = ± = ± 10 ( subtract 7 from both sides )
x = - 7 ± 10
Thus
x = - 7 - 10 = - 17
x = - 7 + 10 = 3
The answer is 6 because a=8
Answer:
−x^3−4x^2+2x+7
Step-by-step explanation:
There are no solutions. By definition of absolute value, , so . The left side will always be positive, and a positive number cannot also be negative.