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3 years ago

Stoichiometry: mole/ mole help

Chemistry

1 answer:

adell [148]3 years ago

4 0

Answer:

0.531 moles of CO₂ are formed.

Explanation:

Given data:

Number of moles of CO = 0.531 mol

Number of moles of CO₂ formed = ?

Amount of oxygen = excess

Solution:

Chemical equation:

2CO + O₂ → 2CO₂

Now we will compare the moles of CO with CO₂.

CO : CO₂

2 : 2

0.531 : 0.531

Thus, 0.531 moles of CO₂ are formed.

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Calculate the mass of aluminum bromide that can be produced from 4.4 mil of bromide

Aloiza [94]

Answer:

197 grams

Explanation:

Without taking into account the number of sig figs you have for your values, you can say that the answer will once again be

197 g of aluminium bromide.

(I hope this is right)

7 0

3 years ago

How many moles of nitroglycerin were in the container originally?

Gemiola [76]

Answer:

4.75

Explanation:

I hope this helped!

7 0

3 years ago

Calculate the pOH of an aqueous solution of .0.073 M LiOH

Novosadov [1.4K]

Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:

[LiOH]= [OH-]= 0.073 M

Replacing in the definition of pOH:

pOH= -log (0.073 M)

pOH= 1.14

In summary, the pOH of the aqueous solution is 1.14

Learn more:

7 0

3 years ago

I am currently practicing for chemistry finals, and i came along this question... can someone explain why the answer is one and

Arte-miy333 [17]

The density of properties will not increase by changing the amount of materials, but only will change if temperature changes because it is the weight per cubic centimeter. For example if you have 20000 grams of gold and its volume is 1040 cubic centimeters, but you also have 550 grams of gold which has a volume of 28.5 cubic centimeters the calculations prove it;

20,000/1040= 19.2 grams per cubic centimeter

as well as 550/28.5= 19.2 grams per cubic centimeter.

6 0

3 years ago

As an FDA physiologist, you need 0.625 L of phosphoric acid acid / dihydrogen phosphate (H3PO4 (aq) / H2PO4 - (aq) ) buffer with

aksik [14]

Answer:

0.4058L of 1.0M H3PO4

0.2192L of 1.5M NaOH

Explanation:

The pKa of the H3PO4 / H2PO4- buffer is 2.12

To solve this question we must use H-H equation for this system:

pH = pKa + log [H2PO4-] / [H3PO4]

2.75 = 2.12 + log [H2PO4-] / [H3PO4]

0.63 = log [H2PO4-] / [H3PO4]

4.2658 = [H2PO4-] / [H3PO4] (1)

Where [] could be taken as the moles of each reactant

As you have H3PO4 solution, the reaction with NaOH is:

H3PO4 + NaOH → H2PO4- + Na+ + H2O

As you can see, both H3PO4 and H2PO4- comes from the same 1.0M H3PO4 solution

The moles of H3PO4 are:

[H3PO4] = Moles H3PO4 - Moles NaOH

And for H2PO4-:

[H2PO4-] = Moles NaOH added

Replacing in (1):

4.2658 = [Moles NaOH] / [Moles H3PO4 - Moles NaOH]

4.2658 Moles H3PO4 - 4.2658 moles NaOH = Moles NaOH

4.2658 Moles H3PO4 = 5.2658 moles NaOH (1)

In volume:

0.625L = Moles H3PO4 / 1.0M + Moles NaOH / 1.5M

0.625 = Mol H3PO4 + 0.6667 Moles NaOH (2)

Replacing (2) in (1):

4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4 / 0.6667)

4.2658 Moles H3PO4 = 5.2658 (0.625 - Mol H3PO4) / 0.6667

4.2658 Moles H3PO4 = 5.2658*(0.9375 - 1.5 mol H3PO4)

4.2658 Moles H3PO4 = 4.9367 -7.8983 mol H3PO4

12.1641 mol H3PO4 = 4.9367

Mol H3PO4 = 0.4058moles * (1L / 1.0moles) =

0.4058L of 1.0M H3PO4

And:

0.625L - 0.4058L =

0.2192L of 1.5M NaOH

5 0

3 years ago