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Tcecarenko [31]
3 years ago
6

If a swimming pool contains 2,850 kiloliters (kL) of water, how many gallons (gal) of water does it contain? (1 gal = 3.785 L)

Chemistry
2 answers:
siniylev [52]3 years ago
6 0

we are given

a swimming pool contains 2,850 kiloliters (kL) of water

2,850 kiloliters (kL)=2850000L

we know that

1gal=3.785L

3.785L=1gal

Firstly , we will find for 1L

1L=\frac{1}{3.785}gal

now, we can multiply both sides by 2850000

2850000*1L=2850000*\frac{1}{3.785}gal

2850000L=2850000*\frac{1}{3.785}gal

2850000L=752972.25892gal

so,

a swimming pool contains 752972.25892gal of water...........Answer


Lesechka [4]3 years ago
5 0

Your answer would be 753,000 gallons of water

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