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3 years ago

If a swimming pool contains 2,850 kiloliters (kL) of water, how many gallons (gal) of water does it contain? (1 gal = 3.785 L)

Chemistry

2 answers:

siniylev [52]3 years ago

6 0

we are given

a swimming pool contains 2,850 kiloliters (kL) of water

2,850 kiloliters (kL)=2850000L

we know that

$1gal=3.785L$

$3.785L=1gal$

Firstly , we will find for 1L

$1L=\frac{1}{3.785}gal$

now, we can multiply both sides by 2850000

$2850000*1L=2850000*\frac{1}{3.785}gal$

$2850000L=2850000*\frac{1}{3.785}gal$

$2850000L=752972.25892gal$

so,

a swimming pool contains 752972.25892gal of water...........Answer

Lesechka [4]3 years ago

5 0

Your answer would be 753,000 gallons of water

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