The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:
0.115 mol I₂
1 - 0.115 = 0.885 mol CH₂Cl₂
We need moles of solute, which we have, and must convert our moles of solvent to kg:
0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂
We can now calculate the molality:
m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂
The molality of the iodine solution is 1.53.
Answer:
45.3 KPa
Explanation:
From the question given above, the following data were obtained:
Total pressure (Pₜ) = 101.3 KPa
Pressure of Hydrogen (Pₕ) = 56 KPa
Pressure of Oxygen (Pₒ) =?
The pressure of oxygen in the mixture can be obtained as follow:
Pₜ = Pₕ + Pₒ
101.3 = 56 + Pₒ
Collect like terms
101.3 – 56 = Pₒ
Pₒ = 45.3 KPa
Thus, the pressure of oxygen in the mixture is 45.3 KPa
You nutted in her left eye
Answer:
c-do background research.
Explanation:
The scientific methods exposes the way scientists carry out their investigation and how findings are reported and at times discarded. It is systematic way of studying perceived observations in the environment.
During the course of an investigation, scientists may seek to find out about the prevailing knowledge about a phenomena and the level of research that might have been done in that regard. It is proper for such a scientist to do a background research by searching for related journals and publications in that field.