The perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.
Option C) is the correct answer.
<h3>What a quadrilateral?</h3>
A quadrilateral is simply a polygon with four sides, four angles, and four vertices.
To get the perimeter, we simply add the values of the four side.
Given that;
The vertices are at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).
To get the dimension between the given coordinates, we use;
d = √((x2 -x1)² +(y2 - y1)²)
For length CD, DE, EF and FC
CD = √((2 - (-2))² + (4 - 1)²) = √( 16+9) = √25 = 5
DE = √((5 - 2)² + (0 - 4)²) = √( 9+16) = √25 = 5
EF = √((1 - 5)² + (-3 - 0)²) = √( 16+9) = √25 = 5
FC = √((-2 - 1)² + ( 1 - (-3))²) = √( 9+16) = √25 = 5
Perimeter of the quadrilateral = CD + DE + EF + FC
Perimeter of the quadrilateral = 5 + 5 + 5 + 5
Perimeter of the quadrilateral = 20units
Therefore, the perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.
Option C) is the correct answer.
Learn more about area of rectangle here: brainly.com/question/27612962
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