The answer to the question is: Yes.
Explanation: It can be solved by following exactly the same procedures
that solved the other two questions that you posted within the past 15 minutes.
Since I'm here already, here is the solution to this one:
6x² + 18x = 0
Divide each side of the equation by 6 :
x² + 3x = 0
Factor the left side:
x(x+ 3) = 0
This statement is true if x=0 or if x=3.
The solution to this one is even the same as the solution to the last one you posted.
You really ought to take a break, go back, review the solutions you've been given,
and try to solve a few on your own.
Answer:
-10 is not a solution to the equation
Step-by-step explanation:
I don't really have an explanation
The "one head and one tail" would be my best guess because you get one of each outcome, whereas the other two outcomes are two of the same outcome.
The sample size should be 250.
Our margin of error is 4%, or 0.04. We use the formula
To find the z-score:
Convert 98% to a decimal: 0.98
Subtract from 1: 1-0.98 = 0.02
Divide both sides by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99
Using a z-table (http://www.z-table.com) we see that this value has a z-score of approximately 2.33. Using this, our margin of error and our proportion, we have:
Divide both sides by 2.33:
Square both sides:
Multiply both sides by n:
Divide both sides to isolate n:
Answer: 64 years
Step-by-step explanation:
Let assume the dealer sold the bottle now for $P, then invested that money at 5% interest. The return would be:
R1 = P(1.05)^t,
This means that after t years, the dealer would have the total amount of:
$P×1.05^t.
If the dealer prefer to wait for t years from now to sell the bottle of wine, then he will get the return of:
R2 = $P(1 + 20).
The value of t which will make both returns equal, will be;
R1 = R2.
P×1.05^t = P(1+20)
P will cancel out
1.05^t = 21
Log both sides
Log1.05^t = Log21
tLog1.05 = Log21
t = Log21/Log1.05
t = 64 years
The best time to sell the wine is therefore 64years from now.