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Dmitrij [34]
4 years ago
6

Whether microorganisms are useful or harmful explain​

Biology
1 answer:
11Alexandr11 [23.1K]4 years ago
3 0

Explanation:

micro organisms , though a large number can cause diseases in plants and animals , including humans . But all microbes arent harmful. a number of microbes are very useful, particularly in industries , agriculture and medicine. In fact, their beneficial effects are far more than the harm they cause.May 20, 2016

Brainly‎ · ‎Installed

Wheth

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Which choice lists the Linnaean taxons in the correct order from least specific to most specific?
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Answer:

a) Kingdom, phylum, class, order, family, genus, species.

Explanation:

Kingdom is the broadest taxonomic category after domain as proposed by Linnaeus. The Linnaean hierarchy of taxon identifies species as the most specific taxon that include only those organisms that can interbreed to produce the fertile progeny.

Several species with some common features are placed in same genus while related genera are placed in same family. Likewise, related families are placed in same order and the related orders are placed in same phylum.

Hence, kingdom is the least specific or broadest taxon that includes all the related phyla while species is the most specific taxon that include only the organisms that can interbreed.

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3 years ago
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In the body, the types of drugs known as steroids act in a way similar to
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Consider a locus with two alleles - A and a. These alleles are codominant, meaning that the fitness of the heterozygote is halfw
bearhunter [10]

Answer:

Question 1.

The mean relative fitness is 0.85

Question 2.

The expected allele frequency change of A, p = 0.63: AA, p2 =0.63 x 0.63 = 0.39.

Explanation:

Mean relative fitness is given as

p2W(AA) + 2pqW(Aa) + q2W(aa).

Where W(AA)= 1.00, W(Aa) = 0.80, W(aa) = 0.60

Firstly, find p2, 2pq, q2 which are the frequencies of AA, Aa and aa respectively.

AA= 500,Aa=250 ,aa=250. Total is 1000

Frequency of A, p=

250/2)+500= 625.

625/1000= 0.625.

Therefore A, p is 0.625

p2 = 0.625x0.625= 0.39

For q, since p+q =1

q= 1 - 0.625 = 0.375

q2= 0.375x0.375=0.14.

2pq= 2x0.625x0.375= 0.47.

Mean relative fitness is

p2W(AA) + 2pqW(Aa) + q2W(aa).

0.39x1+ (0.47x0.80) + (0.14x0.60)=0.85.

Question 2.

From Hardy-Weinberg equilibrium

F = p2 + 2pq + q2.

Frequency of A, p= 0.625 and AA, p2 is 0.625 x 0. 0625= 0.39.

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3 years ago
Scientific name for alkaliphiles
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