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____ [38]
3 years ago
8

A case of tomato cans weighs 563 dekagrams. A case of soup cans weighs 458 dekagrams. How much do the two cases weigh together i

n decigrams? Use the metric table to help answer the question.
Metric Table
kilo- 1,000 hecto- 100 deka- 10 unit 1 deci- 0.1 centi- 0.01 milli- 0.001
o 1,021 decigrams
o 10,210 decigrams
o 102,100 decigrams
0 1,021,000 decigrams

Hurry please i need help.
Mathematics
2 answers:
oee [108]3 years ago
6 0

Answer:

  102,100 decigrams

Step-by-step explanation:

  (564 dag + 458 dag) = 1021 dag

  1021 dag × 100 dg/dag = 102100 dg

The two cases together weigh 102,100 decigrams.

_____

1 dag = 10 g

1 dg = 0.1 g

andriy [413]3 years ago
6 0

Answer:

 102,100 decigrams

Step-by-step explanation:

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sergiy2304 [10]

Answer: 3/10

Step-by-step explanation: (1/5) gallon / (2/3) bin = x gallons / 1 bin cross-multiply

1/5 = (2/3)x multiply both sides by the reciprocal of 2/3 = 3/2

(3/2) (1/5) = x = 3/10 gallons fills the entire bin

Look at it this way......each 1/10 of a gallon fills 1/3 of the bin......so 3(1/10) gallons fills 3(1/3)bins....or

3/10 gallons fills a whole bin...

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2 years ago
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Y varies inversely with x. If y = -8 when x = -7, find the y when x=-4.
lora16 [44]

Answer:

y =-14

Step-by-step explanation:

Inverse variation is of the form

xy = k where k is a constant

(-7)(-8) = k

56 = k

The equation is

xy = 56

Let x = -4

(-4)y = 56

y = 56/-4

y =-14

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3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
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umka2103 [35]

Answer:

0.7361

Step-by-step explanation:

In this question we have

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Then we have a probability of 10% = 0.10

We have q = 1-p

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Then the probability of not more than 1 being defective:

P(x=0) + p(x= 1)

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3 years ago
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olya-2409 [2.1K]
The answer is C.

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