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4 years ago

Could someone help me? I can't understand anything

Mathematics

1 answer:

borishaifa [10]4 years ago

8 0

Answer:

I will only help with number one so you can learn how to do it. If you still dont understand, let me know and ill be here to help.

Step-by-step explanation:

$\frac{x}{4}$ > 21

what you have to do is get the x to be on its own. So we need to get rid of the 4. Since it's a fraction and fractions are division, you need to multiply both sides by 4. The reason as to why you multiply is because multiplication is the opposite if division. By multiplying both sides you get rid of the four and you are left with:

x>84

Again, let me know if you still need help.

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What is the answer to this question

Lesechka [4]

Remark

There's a lot you don't know here. Are DE and GF parallel? Is B a right angle? You can't assume that it is. The safest way to proceed is to give x in terms of 58 and B. You might get an answer that gives you something like 32 but I don't think you can say that unless you are told somewhere that ABC is a right angle triangle with the right angle at B.

So what to do.

<BAC = 58o That's because <BAC = <IAK They vertically opposite.

<ABC + <BAC + <ACB = 180o All triangles have 180o

<ACB = 180 - 58 - <ABC Solve for an unknown angle of a triangle.

<ACB = 122 - <ABC

x = <ACB Vertically opposite angles.

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Answer:

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

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