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Mekhanik [1.2K]
3 years ago
6

Find two consecutive odd integers whose product is 99

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0
The answer to this question is 9 and 11
You might be interested in
Factor: 125x^6-75x^4-20x^2+12
Naddika [18.5K]

Answer:

( 5 2 − 3 ) ( 5 2 − 2 ) ( 5 2 + 2 )

Step-by-step explanation:

8 0
3 years ago
Help pls!<br> simplify<br> -6 x^{2} ÷ 12 - 2(-7)<br><br> a. -17<br> b. 35<br> c. -35<br> d. 11
Mariana [72]

Answer:

11

Step-by-step explanation:

Given: \frac{-6^{2}}{12} -2(-7)

Using PEDMAS rule to solve it.

Now, simplifying:

We first open parenthesis which is (-7) = -7

= \frac{-6^2}{12}-2\times -7

Now, we evaluate the exponent which is -6^2=-36

Next, we divide -36 by 12 to get -3

= \frac{-36}{12}-2\times -7 \\= -3 -2\times -7

Next, we multiply -2 and -7 to get 14

= -3 + 14

Lastly, we add -3 and 14 to get 11

= 11

∴ Answer is 11

5 0
3 years ago
Solve: 2 + 2x=19 + 2x<br> 2=19<br> Answer: No Solutions
riadik2000 [5.3K]

Answer:

no solution

Step-by-step explanation:

2+2x=19+2x

2x-2x=19-2

0=17

6 0
2 years ago
Find an irrational number between -10 and -10.1.
Pavlova-9 [17]
   
Between two rational numbers there are an infinite number of irrational numbers.

Example:


- 5 \sqrt{3} -\sqrt{2}= 5 \times 1.7320508 - 1.41421356 \approx -10.0744676\\\\&#10;-10.1 \ \textless \  -10,0744676 \ \textless \  -10



6 0
3 years ago
Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

7 0
3 years ago
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