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igomit [66]
3 years ago
13

Gbhujiklbvnhjkml dxfcgvhj

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0

Answer:

C.  2 1/2

Step-by-step explanation:

Since there is a distance of 6 1/2 units, you have to add and subtract 6 1/2 from the number.

-4 - 6 1/2 = -10 1/2

-4 + 6 1/2 = 2 1/2

Looking at the answer choices, 2 1/2 can represent point Q.

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Which of the following is the graph of the quadratic function y - x? +10x+16 ?
Assoli18 [71]

Find the vertex:

\textrm{Use the formula } \frac{-b}{2a} \textrm{ to find the vertex}\\ \\ \frac{-10}{2} = -5\\ \\ \textrm{In order to find the y value plug in -5 back into the function}\\ \\ y=(-5)^2+10(-5)+16\\ y=-9\\\\ \textrm{The vertex of the function is} (-5,-9)

Determine if the parabola will open up or down:

a > 0 \\ \\ 1>0

Since the value of a is positive, the parabola will open upwards

Find the x and y intercepts:

Factor y = x^2+10x + 16 to find the x intercepts

(x+8)(x+2)

x + 8 = 0

x = -8

x + 2 = 0

x = -2

x intercepts:

x = -2

x = -8

Find the y intercept

y = 0^2+10(0) + 16\\\\ y=16

Hence, C. Graph A best represents the quadratic function y = x^2+10x + 16

6 0
3 years ago
Solve for Unknown: x/10=43/46.
sergey [27]

Answer:

9

Step-by-step explanation:

x= 430/46

x=9.35 approximately 9( nearest whole number)

4 0
2 years ago
Which of these points, if any, is the midpoint of FJ?
ivanzaharov [21]

The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign

4 + 6 = 10

10/2 = 5

Add 5 to -4

5 + -4 = 1

H is your midpoint

True. As long as AB and BC are on the same line, AB + BC = AC

hope this helps

4 0
3 years ago
BRAINIEST TO WHOEVER RIGHT PLZ HELP
sergejj [24]

Answer:

a)  2.7 sec

b)  2.6 sec

c)  30.3 ft,  1.3 sec

Step-by-step explanation:

graphed the equation and determined answers from the curve

3 0
3 years ago
(F+g)(6) (<br> f+g) 7x+8
pashok25 [27]
I am honestly not sure about this answer... try Khan Academy. Or, try breaking it down into steps.

I hope this helped... sorry about that. I will try this concept soon. :)
6 0
3 years ago
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