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frez [133]
3 years ago
8

Differentiate x²(x + 1):​

Mathematics
2 answers:
notka56 [123]3 years ago
8 0

Answer:

{ \tt{y =  {x}^{2}(x + 1) }} \\  \\  { \tt{ \frac{dy}{dx}  = (2x)(x + 1) + ( {x}^{2})(1) }} \\  \\ { \tt{ \frac{dy}{dx}  = 2 {x}^{2}  + 2x +  {x}^{2} }} \\  \\ { \tt{ \frac{dy}{dx} = 3 {x}^{2} + 2x  }} \\  \\ { \boxed{ \tt{ \frac{dy}{dx} = x(3x + 2) }}}

loris [4]3 years ago
4 0

Answer:

{ tt{y =  {x}^{2}(x + 1) }} \\  \\  { \tt{ \frac{dy}{dx}  = (2x)(x + 1) + ( {x}^{2})(1) }} \\  \\ { tt{ \frac{dy}{dx}  = 2 {x}^{2}  + 2x +  {x}^{2} }} \\  \\ { \tt{ \fac{dy}{dx} = 3 {x}^{2} + 2  }} \\  \\ { \boxed{ \tt{ \frc{dy}{dx} = x(3x + 2) }}}

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is not possible

Step-by-step explanation:

<u><em>The question in English is</em></u>

we are building a road that links the points a = (12 ,21) and b =(17,23) another point is in c =(3,9) it is possible that a single road allows to join these three points?

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope ab

we have

a = (12 ,21) and b =(17,23)

substitute

m=\frac{23-21}{17-12}

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step 2

Find the slope ac

we have

a = (12 ,21) and c =(3,9)

substitute

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simplify

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step 3

Compare slopes ab and ac

The slopes are different

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