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2 years ago

Graph -1,-1 on this graph

Mathematics

1 answer:

TiliK225 [7]2 years ago

4 0

Answer:

so that's how you plot their intersection

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Mia has

Serggg [28]

Answer:

2 7/8

Step-by-step explanation:

first step is making these into improper fractions for example 6 1/8 would equal 49/8 because 6*8=48 and add the 1/8 to get 49/8 then do the same with the 3 1/4 make them into 8ths. so it would be 3 2/8 then 26/8 now subtract 49-26 to get 23/8. now simplify to get 2 7/8

5 0

2 years ago

Read 2 more answers

An expecting mother wants to convert a corner of the nursery in her house into a rectangular playpen by enclosing the corner of

Elena-2011 [213]

10=1+9 1x9=9
=2+8 2x8=16
=3+7 3x7=21
=4+6 4x6=24
=5+5 5x5=25
↑ Left: the possible measurements of the two fences, Right: the possible areas

out of the areas calculated, 25 sq feet is the maximum. :)

Ans: 25 square feet

5 0

3 years ago

The wilsons have triplets and another child who is ten years old. The sum of ages of their children is 37. How old are the tripl

Neko [114]

9. The child is 10 years old, which leaves 37-10, which is 27. Divide 27 by three for the triplets. 27/3 is 9. The triplets are 9 years old

3 0

3 years ago

Read 2 more answers

17 out 22 what percentage is correct

SVETLANKA909090 [29]

The answer is <span>77.2727272727273% hopw this help

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5 0

3 years ago

Find the exact value of each trigonometric function for the given angle θ.

Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

8 0

3 years ago

Graph -1,-1 on this graph​

Graph -1,-1 on this graph