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3 years ago

Can someone please help me ASAP?

Physics

2 answers:

Wittaler [7]3 years ago

8 0

Answer:

Explanation:

marin [14]3 years ago

7 0

Answer:

Reduce the time required for work

Explanation:

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An object of mass 0.50 kg is transported to the surface of Planet X where the object’s weight is measured to be 20 N. The radius

Olin [163]

Answer:

$g'=40\ m.s^{-2}$

Explanation:

Given:

mass of the object, $m=0.5\ kg$

weight of the object on planet x, $W=20\ N$

radius of the planet, $R=4\times10^6\ m$

radial distance between the planet and the object, $r=2\times 10^6\ m$

<u>Now free fall acceleration on planet X:</u>

$W=m.g'$

$20=0.5\times g'$

$g'=40\ m.s^{-2}$ irrespective of the height.

8 0

4 years ago

Read 2 more answers

A 5-kg fish swimming at a speed of 1 m/s swallows an absent-minded 1-kg fish at rest. The speed of the larger fish after lunch i

8090 [49]

Answer:

Explanation:

So:

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⋅

)

(

⋅

−

)

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)

−

0.17

4 0

2 years ago

I need help with these questions

Feliz [49]

7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J

8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m

9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333

6 0

4 years ago

What is a lever and mention its types<br>

Grace [21]

Answer:

Three different types of levers exist, depending on where the input force, fulcrum, and load are. A class 1 lever has the fulcrum between the input force and load. A class 2 lever has the load between the fulcrum and input force. A class 3 lever is a lever that has the input force in between the fulcrum and the load.

Explanation:

3 0

3 years ago

In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to pu

tatuchka [14]

Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

This gravity is split into 2 components on the ramp, 1 parallel and the other perpendicular to the ramp.

We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

F = 20

$294.3sin\theta = 20$

$sin\theta = 20/294.3 = 0.068$

$\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0$

So the ramp cannot be larger than 3.9 degrees

6 0

4 years ago