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Elenna [48]
3 years ago
10

PLEASE HELP GREATLY APPRECIATED IF YOU DO

Physics
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer:

a. 38400j

Explanation:

p= mgh

2400×10×1.6

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suppose that two objects attract each other with a gravitational force of 32 newtons. if the distance between the two objects is
grandymaker [24]

Taking into account the Universal Law of Gravitation, the force of attraction between the tow objects is 8 N.

<h3>Universal Law of Gravitation</h3>

The Universal Law of Gravitation establishes that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.

The Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.

Mathematically it is expressed as follows:

F=G\frac{Mm}{d^{2} }

where:

  • G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ \frac{Nm^{2} }{kg^{2} }.
  • M and m are the masses of the bodies that interact.
  • d is the distance that separates them.

<h3>Force of attraction in this case</h3>

In this case, two objects attract each other with a gravitational force of 32 newtons. The distance between the two objects is doubled.

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

Then, if the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (d²= 2²= 4). The new force is then \frac{1}{4} of the original:

F=\frac{1}{4}×Foriginal

F=\frac{1}{4}×32 N

<u><em>F= 8 N</em></u>

Finally, the force of attraction between the tow objects is 8 N.

Learn more about the Universal Law of Gravitation:

brainly.com/question/15967105

brainly.com/question/11359658

#SPJ1

6 0
2 years ago
At 10:30 AM, detectives discover a dead body in a room and measure its temperature at 27°C. One hour later, the body's temperatu
wolverine [178]

Answer:

The time of death was approximately 4<em><u> hours</u></em> before 10:30 AM.

Explanation:

Temperature of the body when discovered by detective at 10:30 AM= 27°C

After discovery, Temperature of the body at 11.30 AM= 24.8°C

Change in time = ΔT = 1 hour

Rate of change of body temperature with respect to time :

R=\frac{24.8^oC-27^oC}{1 hour}=-2.2^oC/hour

Normal body temperature = 37°C

Change in time since death = ΔT'

R=\frac{27^oC-37^oC}{\Delta T'}

-2.2^oC/hour=\frac{27^oC-37^oC}{\Delta T'}

\Delta T'=\frac{27^oC-37^oC}{-2.2^oC/Hour}=4.54 hour\approx 4 hours

The time of death was approximately 4<em><u> hours</u></em> before 10:30 AM.

4 0
4 years ago
Both car a and car b leave school at the same time, traveling in the same direction. car a travels at a constant speed of 75 km/
Zigmanuir [339]
1)
S₁ = V₁*t = 75*1,7 = 127,5 km

2)
S₂ = V₂*t = 91*1,7 = 154,7 km
4 0
3 years ago
A cyclist is riding a bicycle at a speed of 22 mph on a horizontal road. The distance between the axles is 42 in., and the mass
stealth61 [152]

Answer:

The shortest distance is  S = 24.86 ft

Explanation:

The free body diagram of this question is shown on the first uploaded image

From the question we are told that

   The speed of the bicycle is v_b = 22\ mph = 22 * \frac{5280}{3600}   =  32.26 ft/s

     The distance between the axial is  d = 42 \ in

The mass center of the cyclist and the bicycle is m_c = 26 \ in  behind the front axle

The mass center of the cyclist and the bicycle is m_h = 40 \ in above the ground

   For the bicycle not to be thrown over the

     Momentum about the back wheel must be zero so

                \sum _B = 0

=>             mg (26) = ma(40)

=>             a = \frac{26}{40} g

Here  g = 32.2 ft/s^2

     So     a =  \frac{26}{40} (32.2)

             a =  20.93 ft/s^2

Apply the equation of motion to this motion we have

       v^2 = u^2 + 2as

 Where  u = 32.26 ft /s

             and v = 0 since the bicycle is coming to a stop

        v^2 = (32.26)^2 - 2(20.93) S

=>      S = 24.86 ft        

                 

5 0
3 years ago
PLEASE HELP MEE PLEASE!​
Mariana [72]

Answer:

<h3>Answer C. grams</h3>

Explanation:

I hope you like it

5 0
3 years ago
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