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A jet airplane is in level flight. The mass of the airplane is m=9010kg. The airplane travels at a constant speed around a circu

Lyrx [107]

Answer:

The magnitude of the lift force L = 92.12 kN

The required angle is ≅ 16.35°

Explanation:

From the given information:

mass of the airplane = 9010 kg

radius of the airplane R = 9.77 mi

period T = 0.129 hours = (0.129 × 3600) secs

= 464.4 secs

The angular speed can be determined by using the expression:

ω = 2π / T

ω = 2 π/ 464.4

ω = 0.01353 rad/sec

The direction $\theta = tan^{-1} ( \dfrac{\omega ^2 R}{g})$

$\theta = tan^{-1} ( \dfrac{0.01353 ^2 \times (9.77\times 1609)}{9.81})$

θ = 16.35°

The magnitude of the lift force L = mg ÷ Cos(θ)

L = (9010 × 9.81) ÷ Cos(16.35)

L = 88388.1 ÷ 0.9596

L = 92109.32 N

L = 92.12 kN

3 0

3 years ago

An object is thrown directly up (positive direction) with a velocity (v o ) of 20.0 m/s and d o = 0. How high does it rise (v =

Lelechka [254]

Answer:

h=20.38 m

Explanation:

Given that

Initial speed of object u = 20 m/s

Acceleration $g= 9.8\ \frac{m}{s^2}$

We know that

$v^2=u^2-2gh$

Here acceleration and velocity is in opposite direction so the object will come rest after reaching at distance h.When body will reach at its highest position then velocity will become zero(v=0).

Now by putting the values

$v^2=u^2-2gh$

$0 =20^2-2\times 9.1\times h$

h=20.38 m

5 0

3 years ago

A city bus travels 6 blocks east and 8 blocks north. Each block is 100 m long. If the bus travels this distance in 15 minutes, w

nexus9112 [7]

Answer:

The average speed of the bus, v = 1.55 m/s

Explanation:

Given that,

Number of blocks traveled by bus towards east = 6

Number of blocks traveled by bus towards north = 8

Length of each block = 100 m

Distance traveled by bus towards east 6 x 100 = 600 m

Distance traveled by bus towards north 8 x 100 = 800 m

The total distance traveled, d = 600 + 800 = 1400

Time taken by the bus to travel is, t = 15 minutes

The velocity is given by the formula

v = d/t m

Substituting the values in the above equation

v = 1400 m /(15 x 60) s

= 1.55 m/s

Hence, the average speed of the bus, v = 1.55 m/s

6 0

3 years ago

An lc circuit oscillates at a frequency of 2000 Hz. What will the frequency be if the inductance is quadrupled?

Irina-Kira [14]

<h2>Answer:</h2>

An LC circuits if formed by an inductor and a capacitor. The charge on the capacitor and the current through the inductor both vary sinusoidally with time. Also, energy is transferred between magnetic energy in the inductor and electrical energy in the capacitor. But <em>what happens with the frequency if the inductance is quadrupled? </em>that is, if initially the inductance is $L$ and the frecuency $f=2000Hz$ if now $L_{New}=4L$ What will the frequency be? Well, we know that the frequency, inductance and capacitance are related as:

$f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}}$

and this equals 2000Hz. If now L is quadrupled:

$f_{1}=\frac{1}{2\pi}\sqrt{\frac{1}{4LC}}=\frac{1}{2\pi}\sqrt{\frac{1}{4}}\sqrt{\frac{1}{LC}} \\ \\ \therefore f_{1}=(\frac{1}{2})\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \\ \\ \\ Since \ f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \ then: \\ \\ f_{1}=\frac{1}{2}f \therefore f_{1}=\frac{2000}{2} \\ \\ \therefore \boxed{f_{1}=1000Hz}$

<em>Finally, if L is quadrupled the frequency is half the original frequency and equals 1000Hz</em>

3 0

3 years ago

. What happens to the polarity of an electromagnet when the direction of the current passing through it is reversed?

eduard

Answer:

The polarity of electromagnet also gets reversed when the direction of current is reversed. The current flows from negative terminal to positive terminal in an electromagnet due to the flow of electrons so polarity is also established in the electromagnet. As, the current direction is reversed, the polarity of magnet also gets reversed because the polarity of magnet depends on the direction of the current.

6 0

4 years ago

PLEASE HELP GREATLY APPRECIATED IF YOU DO