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alisha [4.7K]
2 years ago
12

6. The bat hits a ball. What is the

Physics
1 answer:
lana [24]2 years ago
7 0

Answer:

The ball hits the bat

Explanation:

.......

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Describe two ways unbalanced forces help you in your day to<br> day life.
Alexxandr [17]

Answer:

  1. we need unbalance force to lift objects
  2. we need unbalance force to drag objects
6 0
3 years ago
A machine is currently set to a feed rate of 5.921 inches per minute (IPM). Te machinist changes this setting to 6.088 IPM. By h
lukranit [14]

Answer:

By 16.7% or 0.167 IPM

Explanation:

Substracting the final IPM (6.088) to the initial IPM (5.921) gives us the net difference, which is how much did it increase in IPM. Multiplying this number by 100 gives us the percentual increase in the feed rate.

4 0
3 years ago
Read 2 more answers
If santa slides 5.00 m before reaching the edge, what is his speed as he leaves the roof?
AveGali [126]

Even with no friction, it depends on the slope of the roof. That is, it depends on how much elevation (altitude) he loses during the slide.

Whatever that number is ... call it 'h' ... Santa's speed when he reaches the edge is

Square root of (19.6h) meters per second.

It doesn't matter how much he weighs, or how far he has slud. Only how much altitude he lost on the slope while sliding.

8 0
3 years ago
The GPE of a 70kg person standing on a chair 1m off the ground is how many joules?
Artemon [7]
GPE I am assuming is gravitational potential energy. I'll denote it as U for simplicity. 

U = mgy
U = (70kg)(9.81m/s^2)(1m) = 686.7J

U = 686.7J

Hope this helps!
8 0
3 years ago
NEED ANSWERED ASAP!! will give brainliest!
kotegsom [21]
The kinetic energy of any moving object is

            K.E.  =  (1/2) (mass) (speed)² .
 
To use this simple formula, the 'mass' has to be in kilograms,
and the 'speed' has to be in meters-per-second. 

You can see that we have a slight problem that has to be cleaned up:
The speed in the question is given in "kilometers per hour", but we'll
need it in "meters per second".  So let's convert that right now: 

       (600 km/hour) x (1 hour / 3600 seconds) x (1000 meters / km)

    =    (600 x 1 x 1000 / 3600)    (km-hour-meters / hour-second-km)

    =              166.67  meters/second .

Now we're ready to plug numbers into the formula for K.E.

                  (1/2) (mass) (speed)²

            =    (1/2) (80,000 kg) (166.67 m/s)²

            =           (40,000 kg) (27,777.8 m²/s²)

            =                1,111,111,111  kg-m²/s²

            =                 1.1... x 10⁹  Joules   (choice D) 

8 0
3 years ago
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