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3 years ago

5

Line HJ bisects BC at point H BH = 5x - 1 and HC =4x + 3 Frd the length of BC

1 answer:

Levart [38]3 years ago

8 0

Answer:

Step-by-step explanation:

5x - 1 = 4x + 3

x - 1 = 3

x = 4

5(4) - 1 + 4(4) + 3

20 - 1 + 16 + 3

19 + 16 + 3 = 35 + 3 = 38

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I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a

solong [7]

Answer:

$\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}$

Step-by-step explanation:

$40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4$

7 0

3 years ago

the distant around a track is 1/4 mile. a marathon is 26 1/5 miles. How many laps does it take to run a marathon

sleet_krkn [62]

Answer:

108 1/8

Step-by-step explanation:

1/4=0.25, 1/5=0.2

=>26+0.2=26.2

=>26.2/0.25=108.8

8 0

3 years ago

IMPORTANT. LOTS OF POINTS. SOLVE NOW. Rays OM , ON , and OP coincide at time t=0. At the same instant in time, OM and OP begin t

Anton [14]

I believe if Socratic is right the answer is -x+4y=8

6 0

3 years ago

Read 2 more answers

It is 3 miles around Westwood Park exercise trail. After skating around the trail 5½ times, Mr. Zorn lost a wheel. How many mile

mart [117]

I hope this helps you

5 1/2=5.2+1/2=11/2

3.11/2

33/2

15 3/2

16,5

4 0

3 years ago

If it took Carlos 1/2 hour to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 mile

Dvinal [7]

Answer:

Step-by-step explanation:

Given

time taken by Carlos to cycle is $t=0.5\ hr$

For case (1)

Average speed $v_{avg}>16\ ft/s$

For $0.5 hr \approx 30\times 60=1800\ s$

Distance traveled $d=1800\times 16=28,800\ ft\approx 5.45\ miles$

Therefore Carlos might not be able to cover 6 miles with average speed of 16 ft/s

(2) $v_{avg}=18\ ft/s$

for 0.5 hr

distance traveled

$d=1800\times 18=32,400\ ft\approx 6.136$

Therefore Carlos might be able to cover more than 6 miles with $18\ ft/s$

5 0

3 years ago