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insens350 [35]
3 years ago
6

20 POINTSSS

Chemistry
2 answers:
Katena32 [7]3 years ago
5 0

Answer:

D) High temperature and little rainfall

Explanation:

The desert has sunlight  and the other two don't make sense, because there is not much rainfall and the temp is high

nikklg [1K]3 years ago
4 0

Answer:

Its D I took the test

Explanation:

You might be interested in
Be sure to answer all parts.
djyliett [7]

The number of moles contained in each of the question are a) 3.935 and b) 0.001165 mol.

<h3>What are moles?</h3>

Moles are a quantity or amount of a substance. Denoted by n.

To calculate moles, mass is divided by the molar mass

n = m/M

mass is divided by the molar mass

a) 230 grams of NaCl

n = m/M

molar mass of NaCl is 58.44 g/mol

n = 230 / 58.44 = 3.935 mol

b) 0.210 g of aspirin

n = m/M

molar mass of aspirin is 180.158 g/mol

n = 0.210 / 180.158 = 0.001165 mol

Thus, the moles are a) 3.935 and b) 0.001165 mol.

Learn more about moles

brainly.com/question/26416088

#SPJ1

4 0
2 years ago
Linda is learning how to bowl and
raketka [301]
The answer is a throw the ball with greater force
5 0
3 years ago
4. Magnesium and oxygen undergo a chemical reaction to
erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

  1. Convert grams of MgO to moles of MgO.
  2. Moles of MgO to moles of O₂
  3. And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}

3 0
2 years ago
Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. what is the molecular formula for t
Gnesinka [82]

Assuming we have 100 g of sample

30.45/MW of N 14g = 2.175

69.55/MW of O 16g = 4.34

4.34/2.185 = 2

for every 1 mole of N we have 2 moles of O

so the empirical formula would be NO2

without having the molecular weight of the entire molecule the molecular formula can not be determined with the information in your question

6 0
3 years ago
Which salt is produced when NH4OH reacts with HNO3?<br> KNO2<br> NaNO3<br> NH4NO3<br> NH4NO2
xenn [34]

Answer:

NH4NO3 is the answer

Explanation:

Please mark as brainliest

4 0
3 years ago
Read 2 more answers
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