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3 years ago

How many atoms of the element with atomic number 11 are in the reactants of the given formula?

Chemistry

1 answer:

liq [111]3 years ago

3 0

The number of Na atoms in the reactants = 2

<h3>Further explanation</h3>

Every chemical reaction involves compounds that can act as reactants or products

The reactants will react to produce products

The reactants are usually written on the left side of the reaction, while the products on the right side of the reaction

Reaction

2 NaCl + H₂SO₄ → 2 HCl + Na₂SO₄

The element with atomic number 11 = Na(Natrium)

The number of atoms of the element that reacts or is produced can be seen from the reaction coefficient and the number of atoms in the compound

Na in NaCl = 1 atom

From equation, cofficient for NaCl = 2, so number of atoms of Na=2 x 1 = 2

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Answer:

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3 years ago

What reaction conditions most effectively conver a cabocxylic acid to a methly ester?

VLD [36.1K]

Answer:

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Explanation:

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3 years ago

Among the groups of elements listed below, which have the same number of electrons in their outermost energy levels? C, K, Ca, R

tatyana61 [14]

Answer:

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3 years ago

Read 2 more answers

Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under s

Zarrin [17]

Answer:

90.3 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

2 NO(g) + O₂(g) → 2 NO₂(g) ∆H°rxn = –114.2 kJ

We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))

ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol

ΔH°f(NO(g)) = 90.3 kJ/mol

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What is the mass number of 19/9F? Your answer: A. 9 B. 10 C. 19 D. 28

dexar [7]

the mass number of fluorine (F) is 19

C. 19

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3 years ago