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Jobisdone [24]
3 years ago
7

Hydrochloric acid is a strong acid. Acetic acid is a weak acid. Which statement about hydrochloric acid and acetic acid is corre

ct? (1 point)
A. A solution of hydrochloric acid at equilibrium will have a greater concentration of solute than a solution of acetic acid at equilibrium.

B. If the initial concentration of each acid is the same, then acetic acid will produce more H30 ions than hydrochloric acid

C. The pH of a solution of hydrochloric acid must be less than the pH of a solution of acetic acid

D. The dissociation constant for hydrochloric acid is greater than the dissociation constant for acetic acid.​
Chemistry
1 answer:
Flura [38]3 years ago
8 0

Answer:

The dissociation constant for hydrochloric acid is greater than the dissociation constant for acetic acid.

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Aleksandr [31]

Answer:

H2O= +2

CCl4 = +4

Na+= 0

CuCl2= -2

5 0
3 years ago
Hấp thụ hoàn toàn 0,896 lít khí CO2 (đktc) cần dùng 500ml dd Ba(OH)2, thu được m gam kết tủa.
sergeinik [125]

Answer:

Hấp thụ hoàn toàn 0,896 lít khí CO2 (đktc) cần dùng 500ml dd Ba(OH)2, thu được m gam kết tủa.

a) Viết PTHH của phản ứng xảy ra.

b) Tính giá trị của m.

c) Tính nồng độ mol của dung dịch Ba(OH)2 đã dùng.

3 0
3 years ago
Iodine-131 half life 8.040 how long will it take for a 40 gram sample of iodine-131 to decay to 0.75 grams
otez555 [7]

Answer:

See explanation below

Explanation:

To get this, we need to apply the general expression for half life decay:

N = N₀e(-λt)    (1)

Where:

N and N₀ would be the final and innitial quantities, in this case, masses.

t: time required to decay

λ: factor related to half life

From the above expression we need λ and t. To get λ we use the following expression:

λ = t₁₂/ln2   (2)

And we have the value of half life, so, replacing we have:

λ = 8.04 / ln2 = 11.6

Now, we can replace in (1) and then, solve for t:

0.75 = 40 exp(-11.6t)

0.75 / 40 = exp(-11.6t)

ln(0.01875) = -11.6t

-3.9766 = -11.6t

t = -3.9766 / -11.6

<h2>t = 0.34 days</h2><h2></h2>
3 0
3 years ago
When potassium cyanide (KCN) reacts with acids, a deadly poisonous gas, hydrogen cyanide (HCN), is given off: KCN(aq) + HCl(aq)
maks197457 [2]

<u>Answer:</u> The mass of hydrogen cyanide formed is 0.17 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of KCN = 0.420 g

Molar mass of KCN = 65.12 g/mol

Putting values in equation 1, we get:

\text{Moles of KCN}=\frac{0.420g}{65.12g/mol}=0.0064mol

The given chemical equation follows:

KCN(aq.)+HCl(aq.)\rightarrow HCN(g)+KCl(aq.)

As, hydrochloric acid is present in excess. So, it is considered as an excess reagent.

Thus, potassium cyanide is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of potassium cyanide produces 1 mole of hydrogen cyanide.

So, 0.0064 moles of potassium cyanide will produce = \frac{1}{1}\times 0.00064=0.0064mol of hydrogen cyanide

Now, calculating the mass of hydrogen cyanide from equation 1, we get:

Molar mass of HCN = 27.02 g/mol

Moles of HCN = 0.0064 moles

Putting values in equation 1, we get:

0.0064mol=\frac{\text{Mass of HCN}}{27.02g/mol}\\\\\text{Mass of HCN}=0.17g

Hence, the mass of hydrogen cyanide formed is 0.17 grams

3 0
4 years ago
Which of these is not an organism humans,mold,bacteria,lungs
mina [271]
A lung is not a organism 
5 0
3 years ago
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