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skelet666 [1.2K]
3 years ago
11

2. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, o

r no solution. Explain your answers. (a) 4 + 2( − 1) = 10 + 2 (b) 30 − = 10 − (6 + 10) (c) 8x = 4x + 4x + 10(x − x)
Mathematics
1 answer:
Brut [27]3 years ago
7 0

Hello!

To solve algebraic equations, we need to use SADMEP. SADMEP is an acronym used only solve for x in algebraic equations. SADMEP is expanded to be: subtraction, addition, division, multiplication, exponents, and parentheses.

(a) 4 + 2(-1) = 10 + 2 (multiply)

4 + -2 = 10 + 2 (add)

2 = 12

This equation has no solutions because <u>2 is never equal to 12</u>.

(b) 30 = 10 - (6 + 10) (simplify the parentheses)

30 = 10 + -1(16) (multiply)

30 = 10 - 16 (simplify)

30 = -6

This equation has no solutions because<u> 30 and -6 is never equal to each other</u>.

(c) 8x = 4x + 4x + 10(x - x)

8x = 4x + 4x + 10(x - x) (simplify [add and subtract])

8x = 8x + 10(0) (multiply)

8x = 8x  

This equation has an infinite number of solutions because if you <u>substitute any value into the original equation</u>, <u>both sides of the equation</u> will be <u>always equal</u>.

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Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

f(t) = 10000(0.9407)^t

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

f(t) = f(0)(1-r)^t

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that f(0) = 10000, thus:

f(t) = 10000(1-r)^t

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2014 - 2012 = 2, so:

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We use this to find 1 - r.

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8850 = 10000(1-r)^2

(1-r)^2 = \frac{8850}{10000}

(1-r)^2 = 0.885

\sqrt{(1-r)^2} = \sqrt{0.885}

1 - r = 0.9407

Thus

f(t) = 10000(1-r)^t

f(t) = 10000(0.9407)^t

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