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skelet666 [1.2K]
3 years ago
11

2. Solve each given equation and show your work. Tell whether each equation has one solution, an infinite number of solutions, o

r no solution. Explain your answers. (a) 4 + 2( − 1) = 10 + 2 (b) 30 − = 10 − (6 + 10) (c) 8x = 4x + 4x + 10(x − x)
Mathematics
1 answer:
Brut [27]3 years ago
7 0

Hello!

To solve algebraic equations, we need to use SADMEP. SADMEP is an acronym used only solve for x in algebraic equations. SADMEP is expanded to be: subtraction, addition, division, multiplication, exponents, and parentheses.

(a) 4 + 2(-1) = 10 + 2 (multiply)

4 + -2 = 10 + 2 (add)

2 = 12

This equation has no solutions because <u>2 is never equal to 12</u>.

(b) 30 = 10 - (6 + 10) (simplify the parentheses)

30 = 10 + -1(16) (multiply)

30 = 10 - 16 (simplify)

30 = -6

This equation has no solutions because<u> 30 and -6 is never equal to each other</u>.

(c) 8x = 4x + 4x + 10(x - x)

8x = 4x + 4x + 10(x - x) (simplify [add and subtract])

8x = 8x + 10(0) (multiply)

8x = 8x  

This equation has an infinite number of solutions because if you <u>substitute any value into the original equation</u>, <u>both sides of the equation</u> will be <u>always equal</u>.

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Use all of the angle relationships that we have covered to find the missing angles in the puzzle below
Sophie [7]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

I started with triangle GHJ on the right. It is isosceles, so ...

  g = 48°

  h = 2(90 -g) = 84°

  k = 180° -h = 96°

Then, on the lower right, we have ...

  a = 180° -143° = 37°

  b = 143°

  c = e = a = 37°

  f = 90° -e = 53°

At vertex D, we also have ...

  85° +d = b  ⇒  d = 143° -85° = 58°

In triangle DGH, we have ...

  m + d = h  ⇒  m = h -d = 84° -58° = 26°

The sum of angles in triangle DGP is 180°, so ...

  p = 180° -85° -26° = 69°

Finally, ...

  s = p = 69°

  r = 180° -p = 111°

_____

The relationships we used are ...

  • corresponding angles are congruent (at a transversal of parallel lines)
  • alternate interior angles are congruent
  • an exterior angle equals the sum of remote interior angles
  • acute angles in a right triangle are complementary
  • angles in a triangle sum to 180°
  • linear pair angles are supplementary
  • angle sum theorem

7 0
3 years ago
Read 2 more answers
The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.
baherus [9]

Answer:

The approximate difference between m∠C and m∠A is 45° to the nearest degree

Step-by-step explanation:

* Lets talk about the right triangle

- It has one right angle and two acute angles

- The side opposite the the right angle is called hypotenuse

- The other sides are called the legs of the right angle

- In ΔABC

∵ AC is the hypotenuse

∴ ∠B is the right angle

∴ AB and BC are the legs of the right angle

∴ Angles A and C are the acute angles

∵ m∠B = 90°

- The sum of the measures of the interior angles of a Δ is 180°

∴ m∠A + m∠C = 180° - 90° = 90°

- We will use trigonometry to find the measures of angles A and C

- sin A is the ratio between the opposite side to angle ∠A and the

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∵ BC is the opposite side of angle A

∴ sin A = BC/AC

∵ BC = 5 cm

∵ AC = 13 cm

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∴ m∠A = sin^{-1}\frac{5}{13}=22.62

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∵ m∠A + m∠C = 90°

∴ 22.62° + m∠C = 90 ⇒ subtract 22.62 from both sides

∴ m∠C = 67.38°

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5 0
4 years ago
Plz help with any problems you can, show work for number 29
alexgriva [62]

Answer:

For number 13, I think it is rational, integer, and whole number

5 0
3 years ago
How to prove this???
swat32
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go to right side now

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4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\&#10;\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\&#10;~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

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4 0
3 years ago
The table of values below represents a linear function and shows the amount of money in juanitas savings account since she began
makkiz [27]
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8 0
3 years ago
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