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3 years ago

5

Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for

opening night totaled $2071.50. The equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold? adult tickets

2 answers:

nevsk [136]3 years ago

9 0

Answer:168

Step-by-step explanation: First you do 82 times 3.75 which is 307.50. Then you do 2071.5 - 307.5 = 1764 Then you do 1764 divided by 10.50 which is 168

attashe74 [19]3 years ago

4 0

Answer:

Your answer is 168

Step-by-step explanation:

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Z=a/b+c/d solve for A

PilotLPTM [1.2K]

Answer: $a=\frac{b(zd-c)}{d}$

Step-by-step explanation:

Having the following equation given in the exercise:

$z=\frac{a}{b}+\frac{c}{d}$

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract $\frac{c}{d}$ from both sides of the equation:

$z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}$

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

$\frac{zd-c}{d}=\frac{a}{b}$

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

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3 years ago

Given that mCD=20°, find mBC

frosja888 [35]

Answer:

70°

Step-by-step explanation:

$m\widehat {BC} = 90\degree - m\widehat {CD}$

$m\widehat {BC} = 90\degree -20\degree$

$m\widehat {BC} = 70\degree$

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3 years ago

A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches. Approximately how much smaller,

zhuklara [117]

Answer:

$285.74\text{ inch}^2$

Step-by-step explanation:

GIVEN: A bicycle training wheel has a radius of $3\text{ inch}$ . The bicycle wheel has a radius of $10\text{ inch}$ .

TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.

SOLUTION:

radius of bicycle wheel $=10\text{ inch}$

area of bicycle wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times10^2$

$=314\text{ inch}^2$

radius of bicycle training wheel $=3\text{ inch}$

area of bicycle training wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times3^2$

$=28.26\text{ inch}^2$

difference in area of bicycle wheel and bicycle training wheel

$=\text{area of bicycle wheel}-\text{area of bicycle training wheel}$

$=314-28.26$

$=285.74\text{ inch}^2$

hence the training wheel is $285.74\text{ inch}^2$ smaller than regular wheel

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2 years ago

1+4=5 2+5=12 3+6=24 5+8=? What's the answer

Vilka [71]

I have seen this problem before, except it was worded differently. Is this the problem you wished to express?

1+4=5, 2+5=12, 3+6=21, 8+11=?

If so, then your answer is to simply add the last answer to the next problem. If not, then I am afraid I cannot help you.

1+4=5

5+2+5=12

12+3+6=21

21+8+11=40

8 0

3 years ago

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Tpy6a [65]

Answer:

the answer you're looking for is 15

Step-by-step explanation:

hope it help, have a nice day/night

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2 years ago