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Mariulka [41]
3 years ago
11

I need help with this problem

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0
Check out the link for the quizlet up above it is correct
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How do you solve this equation? 8=3(q-10)-10
IRISSAK [1]
Q = 16
View the attached image for work!

6 0
2 years ago
What are congruent triangles?​
jolli1 [7]
Triangles that have all sides and angles the same length or degree.

Please give brainliest
4 0
2 years ago
Read 2 more answers
Which number is prime?<br> 63 <br> 51 <br> 61 <br> 57
kondor19780726 [428]
Hey there!

No numbers go into a prime number other than one and that number. 9 and 7 go into 63, so it’s not 63. 3 and 17 go into 51, so it’s not 51. 19 and 3 go into 57, so it’s not 57. That leaves 61. Nothing goes into this other than one and 61, so the answer is 61.

I hope this helps!
7 0
3 years ago
Solve using Quadratic Formula <br>x^2 + 3x - 3 = 0​
katrin [286]

Answer:

a= 1 , b= 3 , c= –3

x =  \frac{ - b \frac{ + }{}  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 3  \frac{ + }{} {}  \sqrt{ {3}^{2}  - 4(1)( - 3)} }{2(1)}  \\  =   \frac{ - 3 \frac{ + }{}  \sqrt{9 + 12} }{2}  =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\ \\  x =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\  \\ x = 0.79 \\ x =  - 3.79

I hope I helped you^_^

4 0
2 years ago
Is the line through points P(2,-9) and Q(6, -13) perpendicular to the line through points R(5,-1) and
Kay [80]
Line through P(0, 5) and Q(-1, 8):
slope = m = (y2 - y1) / (x2 - x1) = (8 - 5) / (-1 - 0) = 3 / -1 = -3

line through R(3, 3) and S(5, -1):
slope = m = (y2 - y1) / (x2 - x1) = (-1 - 3) / (5 - 3) = -4 / 2 = -2

Parallel lines have equal slopes. Since the two lines have different slopes, they are not parallel.
8 0
2 years ago
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