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andrew11 [14]
4 years ago
12

Suppose that ƒ is an odd function of x. Does knowing that limxs0+ ƒ(x) = 3 tell you anything about limxs0- ƒ(x)? Give reasons fo

r your answer
Mathematics
1 answer:
bonufazy [111]4 years ago
6 0

we are given

f(x) is a odd function

so, f(-x)=-f(x)

-f(x)=f(-x)

now, we are given

\lim _{x\to 0+}f\left(x\right)=3

Let's multiply both sides by -1

-\lim _{x\to 0+}f\left(x\right)=-3

\lim _{x\to 0+}-f\left(x\right)=-3

we have

-f(x)=f(-x)

\lim _{x\to 0+}f\left(-x\right)=-3

now, let's consider y=-x

so, when x--->0+

but for y=-x

y--->0-

now, we can plug it

\lim _{y\to 0-}f\left(y\right)=-3

replace y as x

we get

\lim _{x\to 0-}f\left(x\right)=-3.................Answer

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Mrac [35]
<span><span>1.       </span>The quotient of twice a number p and 14
Let’s identify each
=> the quotient = the answer from division
=> twice a number p = 2p
=> 14
=> 2p / 14
Let’s find the value of p
=> 2p = 14
=> p = 14 / 2
=> p = 7 = the value of a number P is 7
Now, let’s solve
=> 2(7) / 14
=> 14 / 14 = 1 the quotient is 1</span>



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Answer:

12

Step-by-step explanation:

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(10/5 + 13) -3

PEMDAS says parentheses first

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12

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