Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,



Let us take square root of both sides of our equation.


Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
You can plot this by turning the fraction into a decimal. -1&1/3rds is -1.333... and 1/6ths is about .16, so then you can find these points on the number line. Also, the number line has 6 points equal one, so the points by those.
The question ask to find the angle between the given vector to the nearest tenth of a degree and base on the value or the coordinates of each vector, the possible value of the angle base on the said vectors is 1.8 degree. I hope you are satisfied with my answer and feel free to ask for more
Answer:
a+b = 4
Step-by-step explanation:
3(a + b)^2 = 81
(a + b)^2 = 27
a + b = sq rt 27
a + b =
· 
a + b = 3