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emmainna [20.7K]
3 years ago
6

calculate the loan for $10,000, at an annual percentage rate of 5%, for a term of 5 years. what is the amount of accrued interes

t?

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0
2500$ it the interest amount for 5 years

True [87]3 years ago
4 0
The answer to the question is $2500
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Which expression is equivalent to (photo inserted) help asap please
alekssr [168]

The answer would be A!

Whenever there is a fraction in the exponent, the numerator is under the square root, and the denominator is on the outside of the square root!

Additionally, since the negative is outside of the square toot, then it also outside of the parenthesis.

8 0
2 years ago
What is the perimeter of a square whose diagonal is 3 square root 2? Show all work on how you got your answer
Alika [10]

Answer:

12

Step-by-step explanation:

Given: Diagonal of square= 3\sqrt{2}

To find the perimeter of square, we need to find the length of sides of square.

∴ Using the formula of diagonal to find side of square.

Formula; Diagonal= s\sqrt{2}

Where, s is side of square.

⇒ 3\sqrt{2} = s\sqrt{2}

Dividing both side by √2

⇒s= \frac{3\sqrt{2} }{\sqrt{2} }

∴s= 3

Hence, Length of side of square is 3.

Now, finding the perimeter of square.

Formula; Perimeter= 4s

⇒Perimeter= 4\times 3

∴ Perimeter= 12

Hence, Perimeter of square is 12.

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4 years ago
PLEASE HELP ME<br> QUICK PLEEEEAAASE
sasho [114]

Answer:

A 2/6 and 3/6 is the Answer

7 0
3 years ago
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3 years ago
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Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.
Nezavi [6.7K]

Answer:

x=c.a^{-1}.b^{-1}

Step-by-step explanation:

Given equation,

axb = c-----(1)

(axb) ( a^{-1}.b^{-1} ) = c.(a^{-1}b{-1})

(xb)(a)(a^{-1}.b^{-1} ) = c.(a^{-1}b{-1}) ( commutative law of multiplication )

(xb)(a.a^{-1}).b^{-1} = c.a^{-1}b{-1} ( Associative property )

(xb).e.b^{-1} = c.a^{-1}b{-1}

(xb).b^{-1}=c.a^{-1}.b^{-1}   ( identity property )

x.(b.b^{-1})=c.a^{-1}.b^{-1}  ( Associative property )

x.e=c.a^{-1}.b^{-1}      

x=c.a^{-1}.b^{-1}                 ( identity property )

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4 years ago
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