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emmainna [20.7K]
3 years ago
6

calculate the loan for $10,000, at an annual percentage rate of 5%, for a term of 5 years. what is the amount of accrued interes

t?

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0
2500$ it the interest amount for 5 years

True [87]3 years ago
4 0
The answer to the question is $2500
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Is 12.56 bigger than 125.6
VARVARA [1.3K]
No it's smaller. 12.56 is much less than 125.6.

5 0
3 years ago
a company bought 12 boxed lunches from a delli for $74.50 each boxed lunch costs the same amount which equation represents the p
Snowcat [4.5K]
I they each cost 6.21$ caz if u do 6.21 you get 74.53 but if you do 6.20 you get74.40 what ever u prefer
4 0
3 years ago
Anyone know the answer to this
Vesna [10]

Answer:

Part A:

- angle ACB= 60° (ABC equilateral triangle.)

- Angle ECD=EDC= (180°-32°)/2= 148/2= 74° (sum of angles in a triangle is equal to 180, and triangle ECD is isosceles since it's given that CE=DE.

- x= 180°-(60°+74°)

   = 180°-134°

   = 46°

x= 46°

Part B:

120°

3 0
2 years ago
Andrea was given a $700 hiring bonus with her new job she will earn an average commission of $250 per week for the next 15 weeks
Bad White [126]

Answer:

4,450

Step-by-step explanation:

You muiltiply 250 times 15 then you add 700

8 0
3 years ago
Recall Marginal Cost is the derivative of Total Cost, and Fixed Cost is the cost of producing zero units.
olga nikolaevna [1]

Answer:

The total cost of producing 91 units of ACME rocket fuel is $3999.99.

Step-by-step explanation:

The Marginal Cost is given by the following function

MC(q) = 200*(q+9)^{-5}

The total cost function is the integrative of the marginal cost function. So:

TC(q) = \int {MC(q)} \, dq

TC(q) = \int {200*(q+9)^{-5}} \, dq

TC(q) = -50*(q+9)^{-4} + K

In which K, the integrative constant, is the fixed cost. So K = 4000.

1. Find the total cost of producing 91 units of ACME rocket fuel.

This is TC(91).

So

TC(91) = -50*(91+9)^{-4} + 4000 = 3999.99

The total cost of producing 91 units of ACME rocket fuel is $3999.99.

8 0
3 years ago
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