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horsena [70]
3 years ago
5

2/5 kilogram of soil fills 1/3 of a countainer. Can 1 kiligram of soil fit in the container?

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

If 2/5kg fills one third, let's multiply 2/5kg by 3 to find out how much soil the conatainer can hold.

(2/5kg)(3) = 9/5kg = 1.8kg

1.8kg>1kg, so the answer is yes

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What is 8 and 21/40 in decimal form? If don't uderstamd what is 8 and 21 over 40 in decimal form? Plz help thx✌️
Marrrta [24]
It is 8.525. what u do is 21÷40 and get .525 and then u add the 8 in the front and get 8.525
4 0
3 years ago
I would love if someone could help me Thanks in advance
Montano1993 [528]
Answer: Choice A, -1540 feet

----------------------------------

Explanation:

Multiply the rate (44 ft per sec) by the number of seconds (35) to get 44*35 = 1540

The answer will be negative to indicate that the altitude has gone down. If you put in a positive change, then the altitude would go up. So that's why the answer is choice A

Note: when you multiply 44 ft/sec by 35 sec, the "second" units cancel out leaving just feet.

Another note: if you want, think of the 44 as -44 to indicate that the plane is decreasing at a rate of 44 ft/sec

7 0
3 years ago
Ben needs 1 3/8 feet of fabric to make one banner. How many banners can he make from 4 1/2 yards of fabric?
skelet666 [1.2K]

Answer:

x = 9.818

x≈10

The number of banners that can be made are 10

Step-by-step explanation:

We can use the knowledge of proportion to solve this.

First we need to convert yard to feet.

  1  yard      = 3 foot

4 1/2 yard    = y

cross-multiply

y =  4 1/2  ×  3

    =9/2  ×   3

y = \frac{27}{2} feet

This implies 4 1/2 yards =  \frac{27}{2} feet

Let x be the numbers of banners needed to make from 4 1/2 yards of fabric.

1 3/8 feet  = 1 banner

\frac{27}{2}  feets    =    x

cross multiply

1 3/8 × x =  \frac{27}{2}

\frac{11x}{8}  =  \frac{27}{2}

cross-multiply

22x = 216

Divide both-side of the equation by 22

22x/22 = 216/22

x = 9.818

x≈10

The number of banners that can be made are 10

3 0
3 years ago
the blue segment below (7.4) is a diameter of O. what is the length of the radius of the circle. A. 3.7 B. 14.8 C. 11.1 D. 7.4
Salsk061 [2.6K]

Answer:D

Step-by-step explanation:

Not 100%

6 0
3 years ago
Read 2 more answers
What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resi
Romashka-Z-Leto [24]

Answer:

The total resistance is 7.0588\Omega

Step-by-step explanation:

Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: R_1=10\Omega and R_2=24\Omega.

First step: find the total current

For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors (R_1 and R_2).

  • I_{R_1}=\frac{V_S}{R_1}
  • I_{R_2}=\frac{V_S}{R_2}

The total current is:

I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}

I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}

Now, the total resistance (R_{TOTAL}) would be the voltage divided by the total current:

R_{TOTAL}=\frac{V_S}{I_{TOTAL}}

If you replace I_{TOTAL} by the expression obtained previously, the total resistance would be:

R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}

After simplifying the terms you should get:

R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}

Now, you must replace the values of the resistors:

R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega

Thus, the total resistance is 7.0588\Omega

3 0
3 years ago
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