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3 years ago

I don't get how to do #10 someone help plez

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

3 0

I can help but the picture does not load, for some reason it takes me to a page that says enter code. I have no idea what it is but i did not mess with it...
you might want to re-post a new picture just to be safe because that code thing might be something of yours thats personal

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How do I find this, what’s the formula to find the 20th term and can anyone explain the formula? Will award brainliest

harina [27]

Answer:

f(n) = n^2 +1
f(20) = 401

Step-by-step explanation:

The first differences of the sequence are ...

5-2 = 3
10-5 = 5
17-10 = 7
26-17 = 9
37-26 = 11

Second differences are ...

5 -3 = 2
7 -5 = 2
9 -7 = 2
11 -9 = 2

The second differences are constant, so the sequence can be described by a second-degree polynomial.

We can write and solve three equations for the coefficients of the polynomial. Let's define the polynomial for the sequence as ...

f(n) = an^2 + bn + c

Then the first three terms of the sequence are ...

f(1) = 2 = a·1^2 + b·1 + c
f(2) = 5 = a·2^2 +b·2 + c
f(3) = 10 = a·3^2 +b·3 +c

Subtracting the first equation from the other two gives ...

3a +b = 3

8a +2b = 8

Subtracting the first of these from half the second gives ...

(4a +b) -(3a +b) = (4) -(3)

a = 1 . . . . . simplify

Substituting into the first of the 2-term equations, we get ...

3·1 +b = 3

b = 0

And substituting the values for a and b into the equation for f(1), we have ...

1·1 + 0 + c = 2

c = 1

So, the formula for the sequence is ...

f(n) = n^2 + 1

The 20th term is f(20):

f(20) = 20^2 +1 = 401

_____

<em>Comment on the solution</em>

It looks like this matches the solution of the "worked example" on your problem page.

4 0

3 years ago

How can 10% of 82 be used to determine 60% of 82?

myrzilka [38]

Answer:10% of 82 is 820so 60% of 82 is 4800

Step-by-step explanation:

i hope im right

5 0

2 years ago

A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po

igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b) Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c) $z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation

$X_{1}=170$ represent the number of people with the characteristic 1

$X_{2}=110$ represent the number of people with the characteristic 2

$n_{1}=200$ sample 1 selected

$n_{2}=150$ sample 2 selected

$p_{1}=\frac{170}{200}=0.85$ represent the proportion estimated for the sample 1

$p_{2}=\frac{110}{150}=0.733$ represent the proportion estimated for the sample 2

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

a.State the decision rule.

For this case the value of the significanceis $\alpha=0.05$ and $\alpha/2 =0.025$ , we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

$z_{\alpha/2} =1.96$

If the calculated statistic $|z_{calc}| >1.96$ we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8$

c. Compute the value of the test statistic.

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708$

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0

3 years ago

What is 6.84 in word form

alexandr402 [8]

Six point eight four.

(Note, you don't say, "Six point eighty-four" As it doesn't sound correct.

Cheers.

5 0

4 years ago

Read 2 more answers

Shawnda spent $259.20 on a scooter. This was 80% of her budget for a new scooter. How much was the total budget?

just olya [345]

X * 0,8 = 259,2 <=>

x = 258,2/0,8 <=>

x = 322,75

The total budget was 322,75$

7 0

3 years ago