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Lorico [155]
3 years ago
8

Oliver read for 450 minutes this month. His goal is to read for 10% more minutes next month if oliver meets his goal how many mi

nutes will he read in all during the two months
Mathematics
2 answers:
Lunna [17]3 years ago
7 0
945 minutes
450/.1=45
450+45=495
450(month 1)+495(month 2)=945 minutes
larisa [96]3 years ago
6 0
450 minutes this month.
10% more next one.
Total for 2 months.
1) Let's find 10% of 450 and add it to 450 to find out how much he reads next month.
450×0.1=45
450+45=495 minutes
2) Now that we know Oliver reads 495 minutes next month, to find the total, we should add the two.
495+450=First month plus second month=945
•°•Oliver, in total, read 945 minutes during the two months.
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Graph a parabola whose x-intercepts are at x=-3 and x=5 and whose minimum value is y=-4
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Answer:

(See explanation for further details)

Step-by-step explanation:

The standard equation of the parabola is:

y + 4 = C \cdot (x-k)^{2}

The formula is now expanded into a the form of a second-order polynomial:

y + 4 = C\cdot x^{2} -2\cdot C\cdot k \cdot x +C\cdot k^{2}

y = C\cdot x^{2} - (2\cdot C \cdot k) \cdot x + (C\cdot k^{2}-4)

The general equation of the second-order polynomial is:

x = \frac{2\cdot C \cdot k \pm \sqrt{4\cdot C^{2}\cdot k^{2}-4\cdot C\cdot (C\cdot k^{2}-4)}}{2\cdot C}

x = k \pm \frac{\sqrt{C^{2}\cdot k^{2}-C^{2}\cdot k^{2}+4\cdot C}}{C}

x = k \pm 2\cdot \frac{\sqrt{C}}{C}

x = k \pm \frac{2}{\sqrt{C}}

The equations to be solved are presented herein:

-3 = k -\frac{2}{\sqrt{C}}

5 = k + \frac{2}{\sqrt{C}}

Now, the solution of the system is:

-3 +\frac{2}{\sqrt{C}} = 5 -\frac{2}{\sqrt{C}}

\frac{4}{\sqrt{C}} = 8

\sqrt{C} = \frac{1}{2}

C = \frac{1}{4}

k = 5 - \frac{2}{\sqrt{\frac{1}{4} }}

k = 1

The equation of the parabola is:

y = \frac{1}{4}\cdot (x-1)^{2} -4

Lastly, the graphic of the function is included as attachment.

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We are tasked to solve for the smallest angle using the law of cosines given that the three sides of the triangle are 4,5 and 6.
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