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Eddi Din [679]
3 years ago
8

The following graph shows a seventh-degree polynomial:

Mathematics
2 answers:
LenaWriter [7]3 years ago
5 0
Part 1: The zeroes are -5 with a multiplicity of 2, -1 with a multiplicity of 1, 4 with a multiplicity of 3, 7 with a multiplicity of 1.

Part 2: The possible factored form of the function is (x + 8)^2(x + 1)(x - 4)^3(x - 7)
azamat3 years ago
4 0
The answer is included in the picture. 

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Find (a) the circumference and (b) the area of the circle. Use 3.14 or 22/7 for pi. Round your answer to the nearest whole numbe
balandron [24]

Answer:

a)219.8

b)3846.5

Step-by-step explanation:

a) circumference is pi*diameter, so 3.14*70 is 219.8

b) area is pir^2, and radius is 1/2 of diameter, it would be 3.14*35^2, so 3.14*1225, so 3,846.5 in^2.

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288km is he distance
4x72 = 288
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Some months have 30 days, some months have 31 days; how many have 28?
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Anyone? I need help with c.
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In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer
stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = <u><em>percentage of patients stop smoking when given sustained care.</em></u>

So, Null Hypothesis, H_0 : p = 80%     {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, H_A : p \neq 80%     {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here <u>One-sample z test for proportions</u>;

                        T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of patients who stop smoking when given sustained care = 80.2%

           n = sample of patients = 192

So, <u><em>the test statistics</em></u>  =  \frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }

                                     =  0.07

The value of z test statistics is 0.07.

<u></u>

<u>Also, P-value of the test statistics is given by the following formula;</u>

                P-value = P(Z > 0.07) = 1 - P(Z \leq 0.07)

                              = 1 - 0.52790 = 0.4721

<u>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0
3 years ago
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