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Makovka662 [10]
3 years ago
7

PLEASE HELP PREALGEBRA !!!

Mathematics
1 answer:
LekaFEV [45]3 years ago
4 0

The third box as well.

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A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
What is the sum of the interior<br> angles of a polygon that has 7<br> sides?
IgorC [24]

Answer:

900

Step-by-step explanation:

6 0
3 years ago
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How many 16th notes = a half note?
Ber [7]

Answer:

hi so read explanation

Step-by-step explanation:

four sixteenth notes

Four eighth notes equal one- half note in duration and eight eighth notes equal  one whole    note. Two sixteenth notes are to  equal one- eighth note in duration and four sixte enth notes equal one- quarter note in durations. hope dis helped

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3 years ago
If AB=x and x=4, then the transitive property states
Anarel [89]

Answer:

4. AB=4

Step-by-step explanation:

Transitive property is like substitution, or that's how I like to think of it. Since we have 2 common variables and 2 equations, we can "link them together". Replacing x with 4, you get AB=4.

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Find the area of the square if the circumference of the circle is 32.97 in
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Radius r = 32.97 in/ 2pi = 5.247 in. Area is pi·r²

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