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nexus9112 [7]
3 years ago
14

Identify the equation of the parent function, y+x^3, that is horizontally stretched by a factor of 1/5 and reflected over the y-

axis.
Mathematics
2 answers:
levacccp [35]3 years ago
4 0
A horizontal stretching is the stretching of the graph away from the y-axis. When a function is horizontally stretched by a factor, k, the x-value of the function is multiplied by the factor k.

Thus, given the parent function y=x^3, a horizontal stretch by a factor of \frac{1}{5} means that the x-value of the function is multiplied by \frac{1}{5}.

Thus, after a horizontal stretch by a factor of \frac{1}{5} of the parent function y=x^3, we have y=(\frac{1}{5}x)^3.

Refrection of the graph of a function over the y-axis results from adding minus to the x-term of the function.

Thus given the function, y=(\frac{1}{5}x)^3, refrection over the y-axis will result to the function y=(-\frac{1}{5}x)^3.

Therefore, <span>the equation of the function that will result when the parent function, </span><span>y=x^3, is horizontally stretched by a factor of </span><span>\frac{1}{5} and reflected over the y-axis is </span>y=(-\frac{1}{5}x)^3.
tatyana61 [14]3 years ago
4 0

Answer:

Step-by-step A horizontal stretching is the stretching of the graph away from the y-axis. When a function is horizontally stretched by a factor, k, the x-value of the function is multiplied by the factor k.

Thus, given the parent function , a horizontal stretch by a factor of  means that the x-value of the function is multiplied by .

Thus, after a horizontal stretch by a factor of  of the parent function , we have .

Refrection of the graph of a function over the y-axis results from adding minus to the x-term of the function.

Thus given the function, , refrection over the y-axis will result to the function .

Therefore, the equation of the function that will result when the parent function, , is horizontally stretched by a factor of  and reflected over the y-axis is .

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Diano4ka-milaya [45]

Answer:

radius of the sphere (r) = 21 units

Step-by-step explanation:

here's the solution : -

=》

12348\pi =  \frac{4}{3}  \times \pi \times  {r}^{3}

=》

{r}^{3}  = 12348 \times  \frac{3}{4}

( pi cancel out )

=》

{r}^{3}  = 9261

=》

r = 21

4 0
3 years ago
Find the volume of a right circular cone that has a height of 6.7 in and a base with a diameter of 8.8 in. Round your answer to
N76 [4]

Answer: 135.8

Step-by-step explanation:

the formula for this is πr²H/3

π4.4^2x6.7/3

407.5/3

135.8

4 0
3 years ago
Can anyone help me? The top is geometry and the bottom is algebra...
umka21 [38]

Answer:

<u>Geometry</u>

AC equals 13x + 7

<u>Algebra</u>

1. x = -16

2. x = 2

3. 2x^2 - 5x -7

4. (2x + 1)(x - 5)

Step-by-step explanation:

6 0
3 years ago
Describe the difference between algebraic expressions and numerical expressions.
Mila [183]
The difference between an algebraic expression and a numerical expression is that algebraic expressions contain numbers and variables. Numerical expressions only contain numbers. 

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7 0
3 years ago
When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis
Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so \mu = 22, \sigma = 4.

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of X = 30 subtracted by the pvalue of the Z score of X = 10

X = 30

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 22}{4}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 22}{4}

Z = -3

Z = -3 has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

3 0
3 years ago
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