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nexus9112 [7]
3 years ago
14

Identify the equation of the parent function, y+x^3, that is horizontally stretched by a factor of 1/5 and reflected over the y-

axis.
Mathematics
2 answers:
levacccp [35]3 years ago
4 0
A horizontal stretching is the stretching of the graph away from the y-axis. When a function is horizontally stretched by a factor, k, the x-value of the function is multiplied by the factor k.

Thus, given the parent function y=x^3, a horizontal stretch by a factor of \frac{1}{5} means that the x-value of the function is multiplied by \frac{1}{5}.

Thus, after a horizontal stretch by a factor of \frac{1}{5} of the parent function y=x^3, we have y=(\frac{1}{5}x)^3.

Refrection of the graph of a function over the y-axis results from adding minus to the x-term of the function.

Thus given the function, y=(\frac{1}{5}x)^3, refrection over the y-axis will result to the function y=(-\frac{1}{5}x)^3.

Therefore, <span>the equation of the function that will result when the parent function, </span><span>y=x^3, is horizontally stretched by a factor of </span><span>\frac{1}{5} and reflected over the y-axis is </span>y=(-\frac{1}{5}x)^3.
tatyana61 [14]3 years ago
4 0

Answer:

Step-by-step A horizontal stretching is the stretching of the graph away from the y-axis. When a function is horizontally stretched by a factor, k, the x-value of the function is multiplied by the factor k.

Thus, given the parent function , a horizontal stretch by a factor of  means that the x-value of the function is multiplied by .

Thus, after a horizontal stretch by a factor of  of the parent function , we have .

Refrection of the graph of a function over the y-axis results from adding minus to the x-term of the function.

Thus given the function, , refrection over the y-axis will result to the function .

Therefore, the equation of the function that will result when the parent function, , is horizontally stretched by a factor of  and reflected over the y-axis is .

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25 degrees

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All angles add up to 180, so set it up like this:

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