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Olegator [25]
3 years ago
6

Point A (-2,-10) is reflected over the x-axis. Write the coordinates of A'. * (2.-10) O (2.10) O (-2,-10) (-2, 10) Send me a cop

y of my responses. Submit​
Mathematics
1 answer:
Nady [450]3 years ago
4 0

Answer:

(2, -10)

Explanation:

Reflection over the x-axis puts a negative sign on the x value.

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Solve the equation-8+6m= 1/2(4m+16) for m
Lena [83]

Answer:

m = 4

Step-by-step explanation:

Given

- 8 + 6m = \frac{1}{2}(4m + 16) ← distribute parenthesis

- 8 + 6m = 2m + 8 ( subtract 2m from both sides )

- 8 + 4m = 8 ( add 8 to both sides )

4m = 16 ( divide both sides by 4 )

m = 4

6 0
4 years ago
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The admission prices for a small fair are $1.50 for children and $4.00 for adults. In one day there was $5050 collected. If we k
aliina [53]

Answer: 475 adults paid admission

Step-by-step explanation:

1.50c+4a=5050 (1.50 per child and 4 per adult)

1.50(2100)+4c=5050 (2100 children times 1.5 each)

3130+4a=5050

4a=1900

a=475

3 0
3 years ago
PLEASE HELP ME GUYSS!!!
Assoli18 [71]

Answer:

.......................................

3 0
3 years ago
The mean preparation fee H&R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
You lose two points every time you forget to write your name on a test. You have forgotten to write your name for transfer what
Vinvika [58]
the answer is -2........
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