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3 years ago

Select all the pairs of equivalent expressions.

Mathematics

1 answer:

gregori [183]3 years ago

3 0

Answer:

I know that the 4th and 5th equation are correct but I still need to figure out the others but these are what I got hope it helps?

Step-by-step explanation:

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Please help!! i will help you back!!

NeX [460]

Answer:

c = 50

Step-by-step explanation:

Using the Pythagorean Theorem:

Plug in the values of a = 14, and b = 48

$a^{2} +b^{2} =c^{2}\\14^{2} +48^{2} =c^{2} \\c^{2} = 2500\\c = \sqrt{2500} \\c = 50$

7 0

3 years ago

Which of the set of ordered pairs contains the line<br> 1/3 x+y= 15.

Dima020 [189]

Answer: c

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

1. Rich wants to buy a coat priced at x dollars. It is on sale for 20% off. He must

alexandr1967 [171]

Answer: $x-0.20x+0.0725x$

Step-by-step explanation:

Let x be the price. 20% (0.20) 7.25% (0.0725)

$x-0.20x+0.0725x$

6 0

3 years ago

Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q2+11q

Sedbober [7]

Answer:

$(q+\frac{11}{2})^2-\frac{121}{4}$

Step-by-step explanation:

We have been given an expression $q^2+11q$ . We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form $a^2+2ab+b^2$ .

To convert our given expression into perfect square trinomial, we need to add and subtract $(\frac{b}{2})^2$ from our given expression.

We can see that value of b is 11, so we need to add and subtract $(\frac{11}{2})^2$ to our expression as:

$q^2+11q+(\frac{11}{2})^2-(\frac{11}{2})^2$

Upon comparing our expression with $(a+b)^2=a^2+2ab+b^2$ , we can see that $a=q$ , $2ab=11q$ and $b=\frac{11}{2}$ .

Upon simplifying our expression, we will get:

$(q+\frac{11}{2})^2-\frac{11^2}{2^2}$

$(q+\frac{11}{2})^2-\frac{121}{4}$

Therefore, our perfect square would be $(q+\frac{11}{2})^2-\frac{121}{4}$ .

8 0

3 years ago

Read 2 more answers

You attend a wedding and are second in line to get a slice of wedding cake. there are 3 slices of vanilla cake, 12 slices of cho

Dima020 [189]

Answer:

1/14

Step-by-step explanation:

Let A represent the event First person getting red velvet cake
Let B represent the event Second person getting red velvet cake

P(A) = Total number of Red Velvet Cakes ÷ Total Number of Cakes =

6/21 = 2/7

If the first person gets a red velvet cake, then there are 5 red velvet cakes and 20 total cakes

Therefore P(B|A) = Number of red velvet cakes left ÷ total number of cakes left = 5/20 = 1/4

P(A and B) == probability of both getting red velvet cake P(A∩B) = P(A).P(B|A) = 2/7 × 1/4 = 2/28 = 1/14

7 0

2 years ago