(-3/2, 27\4) is the vertex it opens down max at the vertex mins are negative infiity x intercepts at -1 and 3 y intercept at (0,0)
I think it's the double of the area of one of the squares
X^3 - 3x^2 + 5x - 15
x^2(x-3) +5(x-3)
(x^2 + 5)(x - 3) <==Answer
(2,12). Moving left to right is the x, moving up and down is the y.
Answer:
Step-by-step explanation:
The formula for the area of a square is A = x^2, where x is the length of one side. Equivalently, x^2 = A.
Here x^2 = 225 yd^2. Taking the positive square root of both sides, x = 15 yd.
Thus, the perimeter of the square area enclosed by the fence is
P = 4(15 yd) = 60 yd
